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omeli [17]
3 years ago
5

The first Portuguese explorer to lay claim to Brazil was

Mathematics
1 answer:
Serhud [2]3 years ago
6 0

Answer:

Cabral is right

Step-by-step explanation:

Mark me brainleyest plz

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Help meeeeeeeeeeeeeeee
Reil [10]

Answer:

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used

Step-by-step explanation:Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be usedDrag the tiles to the correct boxes to complete the pairs. Not all tiles will be used

7 0
3 years ago
Read 2 more answers
Can to answer all 4 please?
Tasya [4]
1) A - yes, b - no, c -  yes
2) false, true, false
3) 85p - 34%
      xp - 66%
x = 165 - she has to read 165 more pages.
4) Sylvia earns 84/12 = 7$/hr
maximum she can earn is 7*15 = 105 $
she will earn 105$ if she works for 15 hours
5 0
3 years ago
Jamie purchased a condo in Naples, Florida, for $699,000. She put 20% down and financed the rest at 5% for 35 years. What are Ja
EleoNora [17]
The payments are ...
  A = P(r/n)/(1 -(1+r/n)^(-nt))
where P is the principal amount, $699,000*0.80 = $559,200
  r is the annual interest rate, 0.05
  n is the number of compoundings per year, 12
  t is the number of years.
Then
  A = 559,200*(0.05/12)/(1 -(1 +0.05/12)^(-12*35)) = 2822.21

The total of 420 of these payments is $1,185,328.20, which is $626,128.20 more than the loan amount.

Jamie's total finance charge is about $626,128.20.


_____
There is always some minor adustment required in the amount of the last payment. That has not been taken into account here.
8 0
3 years ago
Use sigma notation to represent the sum of a geometric series with a first term of 3 and a common ratio of . A. B. C. D.
maksim [4K]

Answer:

\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]

Step-by-step explanation:

A geometric sequence is a list of numbers having a common ratio. Each term after the first is gotten by multiplying the previous one by the common ratio.

The first term is denoted by a and the common ratio is denoted by r.

A geometric sequence has the form:

a, ar, ar², ar³, . . .

The nth term of a geometric sequence is ar^{n-1}

Therefore the sum of the first n terms is:

\Sigma_{k=1}^{n}(ar^{k-1})

Given a geometric series with a first term of 3 and a common ratio of 10/9, the sum of the first n terms is:

\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]

5 0
3 years ago
Can someone please help me
umka2103 [35]

Answer:

28/43

Step-by-step explanation:

The question asks what is the probability that Marley picks out a blue or yellow marble.

In total, there are 43 marbles.

In total, there are 28 blue and yellow marbles. (18+10=28)

So, the answer would be 28/43

Hope this helps

6 0
3 years ago
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