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omeli [17]
3 years ago
5

The first Portuguese explorer to lay claim to Brazil was

Mathematics
1 answer:
Serhud [2]3 years ago
6 0

Answer:

Cabral is right

Step-by-step explanation:

Mark me brainleyest plz

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A student said that since –9 is less than 4, then |–9| is less than |4|. Is the student correct? Explain why or why not
Leno4ka [110]
The student is not correct.

Absolute value means distance from zero
|-9| = 9
|4| = 4

Since 9 is greater than 4,
|-9| is greater than |4|

In other words, -9 is further from zero then 4
5 0
3 years ago
at the local baseball diamond,the distance from home base to second base is 100 feet. Determine the distance from home base to f
Archy [21]

Answer:

  70.7 ft

Step-by-step explanation:

The triangle formed by home plate, first base, and second base is an isosceles right triangle with hypotenuse 100 ft. Then the side length (base-line distance between bases) is (100 ft)/√2 ≈ 70.7 ft.

___

For an isosceles right triangle with side lengths 1, the hypotenuse can be found from the Pythagorean theorem to be ...

  hypotenuse = √(side² + side²) = √(1²+1²) = √2

Then the diamond distances satisfy the proportion ...

  hypotenuse/side = 100 ft/(base distance) = √2/1

or ...

  base distance = (100 ft)/√2 ≈ 70.71068 ft

8 0
3 years ago
Diane has 12 coins that total $1.60. If the coins are all nickels and
Dmitry_Shevchenko [17]

Answer:

she has 4 quarters because 4 quarters equals $1 and she has 12 nickles because 12 × 5 =60

6 0
3 years ago
Circle K has a diameter of 24 inches. Find the exact length of semicircle HJI. In your final answer, include all of your calcula
Svet_ta [14]
A semicircle's perimeter is half the perimeter of the complete circle.

The perimeter of the complete circle is its circumference which is found by the equation: πD.

Then the equation of the perimeter of the semicircle is πD/2

In this case D = 24 in, then the perimeteir is π (24in/2) = 12π in ≈ 37.7 in

Answer: The exact length is 12π inches and the approximate length is 37.7 inches


4 0
3 years ago
Read 2 more answers
My watch is 5 minutes slow, but i think it is 3 minutes fast. I arrive 'on time' according to my calculations to catch the 1:15
faltersainse [42]
1:15 pm + 5 minutes =1:20 PM  You add 5 minutes because your watch is slow then subtract 3 minutes because you thought the watch was 3 minutes fast. real time is 1:17 PM
 1:20 pm  - 3 minutes = 1:17 PM
4 0
3 years ago
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