Elimination would be the best
Answer:
The correct option is C. either a t test or an analysis of variance can be performed.
Step-by-step explanation:
Consider the provided information.
- The t-test, is used for whether the means of two groups are equal or not. The assumption for the test is that both groups are sampled from normal distributions with equal variances.
- Analysis of Variance (ANOVA) is a statistical method evaluating variations between two or more methods. ANOVA is used in a study to analyze the gaps between group methods.
- ANOVA is used not for specific differences between means, but for general testing.
- The chi-squared test is often used to evaluate whether there was a significant difference in one or more groups between the predicted frequencies and the observed frequencies.
Hence, Either a t test or an analysis of variance can be performed to determine whether the means of two population are equal.
Therefore, the correct option is C. either a t test or an analysis of variance can be performed.
Answer:
Step-by-step explanation:
Given that there are 3 events as
rolling 3 dice, are the events A: sum divisible by 3 and B: sum divisible 5
The sample space will have
(1,1,1)...(6,6,6)
Sum will start with 3 and end with 18
Sum divisible by 3 are 3,6,9..18
Sum divisible by 5 are 5,10,....15
The common element is 15
Hence these two events are not mutually exclusive.
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