Question

Question 3. Find the distance between P(4,5) and the line with equation 8x + 5y = 20​

Answer 1

Answer:

Step-by-step explanation:

8x+5y = 20

y = (-8/5)x + 4

slope of the line is -8/5.

slope of any perpendicular to the line is ⅝.

line of slope ⅝ that passes through P(4,5):

y-5 = ⅝(x-4)

y = ⅝x + 2.5

find intersection of lines

⅝x + 2.5 = (-8/5)x + 4

25x + 100 = -64x + 160

89x = 60

x = 60/89, y = 260/89

distance between (60/89, 260/89) and (4,5) = 3.92