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2 years ago

What is 65% of 20? ye

Mathematics

2 answers:

irga5000 [103]2 years ago

5 0

Answer:

Step-by-step explanation:

x/20 = 65%/100

20 x 65 = 1300

1300 divided by 100 = 13

Fantom [35]2 years ago

4 0

Answer:13

First you have to turn the percent into a decimal, and then multiply it by the original number.

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50 pounds to 35 pounds percentage of change

iVinArrow [24]

Answer:

30%

Step-by-step explanation:

<h2><u>Percentage change </u></h2><h3>formula :</h3>

$\frac{change}{origional} * 100$

= 50 - 35 = 15

= $\frac{15}{50}*100\\$

4 0

3 years ago

Help me plzzzzzzzzzzzzz

andreyandreev [35.5K]

Answer:

Q1.

a. three hundred sixty-four thousand eight hundred twenty-five

b. one hundred forty-three

c. nine hundred four thousand three hundred six

d. seven million twenty

e. fifty-six million thirty thousand one hundred twenty-three

f. six thousand twenty-four

g. two hundred four

h. six hundred seventy-four thousand one

i. nine hundred sixty-two thousand three hundred forty-two

Q2.

a. 5000000

b. 1000004

c. 60000203

d. 1311

e. 286

f. 34503271

g. 844536

h. 3748

i. 125064

j. 4605231

5 0

3 years ago

How much more pizza is in a 12-in. diameter pizza than an 8-in. diameter pizza?

Kazeer [188]

A = pi * r^2
A = 3.14 * 16
A = 50.24 square inches
50.24 / 12 = _______ square inches
geometry - Becky, Saturday, May 4, 2013 at 7:44pm 4.2

5 0

3 years ago

Read 2 more answers

An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.

Greeley [361]

Answer: 1) 0.6561 2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel. : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = $P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}$

$=(1)(0.90)^4=0.6561$

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= $P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037$

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

8 0

3 years ago

Claire walked her dog 2 1/5 miles. Carson walked her dog 1 3/4 times as far as Claire did. How many more miles did Carson walk h

Anon25 [30]

The word "times" means you have to multiply.

2 1/5 times 1 3/4 is 3 17/20.

The phrase "how many more" means you have to subtract.

3 17/20 minus 2 1/5 is 1 13/20.

Carson walked her dog 1 13/20 more miles than Claire did.

Sorry for the lazy explanations Imao

6 0

3 years ago