First in order to solve you need to get rid of the fraction. You can do so by multiplying to entire equation by the denominator like so...
5(5r - 1/5) = (4/5)5
25r - 1 = 4
Then to isolate the variable you need to add 1 to both sides.
25r = 5
Then you divide.
r = 5/25
Simplify.
r = 1/5
I hope this helps love! :)
The solution for this task is: 13+5=18 18*2=36
Answer: No, x+3 is not a factor of 2x^2-2x-12
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Explanation:
Let p(x) = 2x^2 - 2x - 12
If we divide p(x) over (x-k), then the remainder is p(k). I'm using the remainder theorem. A special case of the remainder theorem is that if p(k) = 0, then x-k is a factor of p(x).
Compare x+3 = x-(-3) to x-k to find that k = -3.
Plug x = -3 into the function
p(x) = 2x^2 - 2x - 12
p(-3) = 2(-3)^2 - 2(-3) - 12
p(-3) = 12
We don't get 0 as a result so x+3 is not a factor of p(x) = 2x^2 - 2x - 12
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Let's see what happens when we factor p(x)
2x^2 - 2x - 12
2(x^2 - x - 6)
2(x - 3)(x + 2)
The factors here are 2, x-3 and x+2
Answer:
You multiply 5 by 1/5 to get 1. So with 2x, you multiply by 1/(2x) to get 1. That's about all you know, since we only know that x is positive.
Step-by-step explanation:
total book =1
1/5 + 2/3 + wed = 1
get a common denominator of 15
1/5 * 3/3 + 2/3 * 5/5 + wed = 1 * 15/15
3/15 + 10/15 + wed = 15/15
combine like terms
13/15 + wed = 15/15
subtract 13/15 on each side
wed = 15/15-13/15
wed = 2/15
He read 2/15 of the book on Wednesday
