To calculate for the z-score we use the formula:
z=(x-μ)/σ
thus the answers to questions will be as follows:
a]<span>Carmen purchased a 16-ounce can of Nut Munchies and counted 100 peanuts. What is the z-score for this can of peanuts?
</span>x=100
μ=96.3
σ=2.4
z=(100-96.3)/2.4
z=1.542
b]<span>Angelo purchased a 20-ounce can of Gone Nuts and counted 116 peanuts. What is the z-score for this can of peanuts?
x=116
</span>μ=112.6
σ=2.8
<span>thus
z=(116-112.6)/2.8
z=1.214
c]</span><span>Carmen declares that purchasing her can of Nut Munchies with 100 peanuts is less likely than Angelo purchasing a can of Gone Nuts with 116 peanuts. Is Carmen’s statement correct? Use the definition of a z-score to support or refute Carmen’s claim.
This is very correct because because by definition of z-score, Munchies with 100 peanuts is 1.542 away from the mean as compared to Munchies with 116 peanuts which is 1.214 standard deviations from the mean hence the higher likelihood. </span>
A.) 32 degrees fahrenheit
B.) 212 degrees fahrenheit
C.) 59 degrees fahrenheit
Answer:
the third answer
Step-by-step explanation:
