Question

If it runs with a velocity of -3 m/s for 3 seconds and then a velocity of 2 m/s for 4 seconds, what is it's displacement?

Answer 1

Answer:

The displacement from the given data is 17 m.

Explanation:

Given;

initial velocity, u = -3 m/s

time of motion, t = 3 s

final velocity, v = 2 m/s

time of motion, t = 4 s

The initial position is calculated as follows;

x₁ = ut

x₁ = -3 x 3

x₁ = -9 m

The final position is calculated as follows;

x₂ = vt

x₂ = 2 x 4

x₂ = 8 m

The displacement is calculated as follows;

Δx = x₂ - x₁

Δx = 8 m - (-9m)

Δx = 8m + 9m

Δx =  17 m

Therefore, the displacement from the given data is 17 m.