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In-s [12.5K]
3 years ago
8

Vector r = <-3, 5> and vector s = <-5, 8>. Determine r + s

Mathematics
1 answer:
BigorU [14]3 years ago
4 0

Answer:

< - 8, 13 >

Step-by-step explanation:

r + s

= < - 3, 5 > + < - 5, 8 > ← add corresponding components of the vectors

= < - 3 - 5, 5 + 8 >

= < - 8, 13 >

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(20,-3) (19,-20) formula is: y2-y1/x2-x1
Orlov [11]

Answer:

17

Step-by-step explanation:

The first thing to do is plug in the numbers for the equation. Starting with:

[-20-(-3)]/(19-20)

When you answer that you simplify the answer to

(-20+3)/(19-20)

You answer what is in the parenthesis first.

(-17)/(-1)

After this step you simplify.

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6 0
3 years ago
Read 2 more answers
The ages of adults in a certain community follow a normal distribution with mean 38 and standard deviation 6. The random variabl
nataly862011 [7]

Answer:

a = 33.32

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 38, \sigma = 6

P(32 < x < a) = .0590

This is the pvalue of Z when X = a subtracted by the pvalue of Z when X = 32.

X = 32

Z = \frac{X - \mu}{\sigma}

Z = \frac{32 - 38}{6}

Z = -1

Z = -1 has a pvalue of 0.1587

X = a

p - 0.1587 = 0.0590

p = 0.0590 + 0.1587

p = 0.2177

So when X = a, Z has a pvalue of 0.2177. So when X = a, Z = -0.78.

Z = \frac{X - \mu}{\sigma}

-0.78 = \frac{X - 38}{6}

X - 38 = -0.78*6

X = 33.32

So a = 33.32

3 0
3 years ago
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