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3 years ago

Solve the inequality -5(d-2)>35

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

8 0

Answer:

d < -5

Step-by-step explanation:

Okay, so the equation is -5(d-2)>35

First we have to use distributive property to get rid of the parenthesis.

we do -5(d) --> -5d

then, -5(-2) --> 10

So now we just redo the equation---

-5d + 10 > 35

now you have to isolate d, the variable

First, to isolate you have to get rid of 10. Subtract 10 on both sides.

-5d + 10 > 35

- 10 -10

----------------------

-5d > 25

Then you have -5d > 25. You have to do the opposite operation again to make the d by itself, so you divide -5 on each side.

-5d > 25

----- -----

-5 -5

-5d/-5 is d because the -5's cancel out. 25/-5 is -5. Now, you have to flip the equation because when working with inequalities, you have to flip the symbol.

SO,,, the answer is

d < -5

Hope this helps!!

-Ketifa

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3 years ago

Two students from a group of eight boys and 12 girls are sent to represent the school in a parade.If the students are chosen at

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Answer:

The probability that the students chosen are not both girls is 62/95 ⇒ (c)

Step-by-step explanation:

* Lets explain how to find the probability of an event

- The probability of an Event = Number of favorable outcomes ÷ Total

number of possible outcomes

- P(A) = n(E) ÷ n(S) , where

# P(A) means finding the probability of an event A

# n(E) means the number of favorable outcomes of an event

# n(S) means set of all possible outcomes of an event

- Probability of event not happened = 1 - P(A)

- P(A and B) = P(A) . P(B)

* Lets solve the problem

- There is a group of students

- There are 8 boys and 12 girls in the group

∴ There are 8 + 12 = 20 students in the group

- The students are sent to represent the school in a parade

- Two students are chosen at random

∴ P(S) = 20

- The students that chosen are not both girls

∴ The probability of not girls = 1 - P(girls)

∵ The were 20 students in the group

∵ The number of girls in the group was 12

∴ The probability of chosen a first girl = 12/20

∵ One girl was chosen, then the number of girls for the second

choice is less by 1 and the total also less by 1

∴ The were 19 students in the group

∵ The number of girls in the group was 11

∴ The probability of chosen a second girl = 11/19

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∴ The probability of both girls = (12/20) × (11/19) = 33/95

- To find the probability of both not girls is 1 - P(both girls)

∴ P(not both girls) = 1 - (33/95) = 62/95

* The probability that the students chosen are not both girls is 62/95

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3 years ago

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Rounded these check below for full answers

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b.)

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c.)

two or more failures is equa lto

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Answer:

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Step-by-step explanation:

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