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2 years ago

I need help on B-D.....

Mathematics

2 answers:

ella [17]2 years ago

8 0

~ Substitute x = 2 into the equation and if the result is equal to the y- coordinate of the point then it is a solution.

~ y = 3(2) - 2 = 6 - 2 = 4 ≠ - 1

(2, - 1) is not a solution to the equation.

~ The point (2, - 1) only lies on the line sloping downwards from left to right.

~ So it’s is a solution to that equation.

Brums [2.3K]2 years ago

7 0

Answer:

see explanation

Step-by-step explanation:

To determine if (2, - 1) is a solution to y = 3x - 2

Substitute x = 2 into the equation and if the result is equal to the y- coordinate of the point then it is a solution.

y = 3(2) - 2 = 6 - 2 = 4 ≠ - 1

Thus (2, - 1) is not a solution to the equation.

The point (2, - 1) only lies on the line sloping downwards from left to right.

It is therefore a solution to that equation but not the other.

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Answer:

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Step-by-step explanation:

1) A polynomial is an algebraic expression of the form $p(x) = \Sigma \limits_{i = 0}^{n} c_{i}\cdot x^{i}$ , where $n$ is the grade of the polynomial. In this case, the only equation that satisfies this definition is:

$y = -\frac{3}{2}\cdot x^{12} -7\cdot x^{5}+\frac{2}{3}\cdot x -10$

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$p(x) = (2\cdot x + 1)\cdot (5\cdot x^{3}) -(2\cdot x +1)\cdot (8\cdot x) + 4\cdot (2\cdot x + 1)$

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We see that coefficients for $x^{2}$ and $x$ are -16 and 0, respectively. Hence, the incorrect answer is E.

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