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const2013 [10]
3 years ago
14

The special drink of the month was iced mocha. The shop sold 5 times as many ice mochas in one week as hot mochas. How many more

iced mochas were sold than hot mochas in 4 weeks? Explain?
There’s a picture of the table

Mathematics
2 answers:
Crank3 years ago
5 0

Answer:

533 iced mochas were sold more than the hot mochas.

Step-by-step explanation:

We are given the following information in the question:

Let x be the number of hot mochas sold and y be the number of iced mochas sold.

Total number of mochas sold in a week = 200

Thus, this can be represented in the form of equation as:

x+y = 200

The shop sold 5 times as many ice mochas in one week as hot mochas.

Thus, we can write this in the form of equation as:

y = 5x

Solving the two equation:

x + 5x = 200\\6x = 200\\\\x = \displaystyle\frac{200}{6}

y = \displaystyle\frac{1000}{6}

Now, number of hot mochas sold in 4 week =

\text{Number of hot mochas sold in 1 week}\times 4 =\\\\ \displaystyle\frac{200}{6}\times 4 = \frac{800}{6}

Number of iced mochas sold in 4 weeks =

\text{Number of iced mochas sold in 1 week}\times 4 =\\\\ \displaystyle\frac{1000}{6}\times 4 = \frac{4000}{6}

Number of iced mochas sold more than hot mochas in 4 weeks =

\text{Number of iced mochas sold in 4 weeks} - \text{Number of hot mochas sold in 4 weeks}\\\\= \displaystyle\frac{4000}{6}- \frac{800}{6} = \frac{3200}{6} = 533.33 \approx 533

Hence, 533 iced mochas were sold more than the hot mochas.

-BARSIC- [3]3 years ago
4 0
200 +5(200) = 1200 mochas a week in total
They sold 1000 iced mocha in a week
200 x 4=800 hot mochas in 4 weeks
1000 x 4=4000 iced mochas in 4 weeks
They sold 4000-800= 3200 more iced mochas in 4 weeks
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Find the line y=a+bx which best approximates the data points
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Answer:

y = 11.84x - 32.71

Step-by-step explanation:

Here, the given data points,

(−3,−70),(−1,−42),(1,−21),(2,−9),(4,14),

Let x represents the input value and y represents the output value,

So, the table that represents the given situation is,

x         -3            -1             1             2             4

y       -70          -42         -21         -9             14

By the above table,

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Let the equation of the line is,

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Where,

a=\frac{\sum y \sum x^2 - \sum x\sum xy}{n(\sum x^2)-(sum x)^2}

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