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Olin [163]
3 years ago
12

What is the area of the rhombus shown below?

Mathematics
2 answers:
HACTEHA [7]3 years ago
8 0

Answer: C: 110.5

Step-by-step explanation:

Sophie [7]3 years ago
5 0

Answer:

answer is A

Step-by-step explanation:

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Which statement is true?
natka813 [3]
Every square is a rectangle<span> because it is a quadrilateral with </span>all<span> four angles right angles.</span>
7 0
3 years ago
Find the missing side. round to the nearest tenth.
horrorfan [7]

Answer:

24) x = 9.2

25) x = 30.8

Step-by-step explanation:

Given

See attachment for triangles

Solving (24)

To solve for x, we make use of cosine formula

i.e.

cos(40) = adjacent ÷ hypotenuse

So, we have:

cos(40) = x ÷ 12

Multiply both sides by 12

12 cos(40) = x

12 * 0.7660 = x

x = 9.2

Solving (25)

To solve for x, we make use of sine formula

i.e.

sin(25) = opposite ÷ hypotenuse

So, we have:

sin(25) = 13 ÷ x

Multiply both sides by

x sin(25) = 13

Divide by sin(25)

x = 13 ÷ sin(25)

Using a calculator

x = 30.8

5 0
2 years ago
Sara had some buns she sold 5/9 of them, if she has 128 buns left. How many bums did she have at first?
mina [271]

Step-by-step explanation:

Maybe she had

128 + 9 = 137 buns

7 0
3 years ago
Read 2 more answers
(40 POINTS)
Y_Kistochka [10]

Answer:

1.  f(0) =  501170

2.  decreasing

3.  2% decrease

4. 302438

Step-by-step explanation:

In 1995 x=0

f(x) = 501170(0.98)^0

f(0) =  501170

The population is decreasing since we are multiplying by .98 ^x

.98 is less than 1 so it is getting smaller each time.

1 -.98 = .02

It is decreasing by 2 % each year

2020-1995  =25 years

f(25) = 501170(0.98)^25

        =302438.41862

Rounding to the nearest whole number

          302438

7 0
3 years ago
A random sample of n observations is selected from a normal population to test the null hypothesis that muμequals=10. Specify th
brilliants [131]

Answer:

Step-by-step explanation:

a) H0: μ = 10

Ha: μ ≠ 10

This is a two tailed test

n = 13

Since α = 0.01, the critical value is determined from the t distribution table. Recall that this is a two tailed test. Therefore, we would find the critical value corresponding to 1 - α/2 and reject the null hypothesis if the absolute value of the test statistic is greater than the value of t 1 - α/2 from the table.

1 - α/2 = 1 - 0.01/2 = 1 - 0.005 = 0.995

The critical value is 3.012

The rejection region is area > 3.012

b) Ha: μ > 10

This is a right tailed test

n = 23

α = 0.1

We would reject the null hypothesis if the test statistic is greater than the table value of 1 - α

1 - α = 1 - 0.1 = 0.9

The critical value is 1.319

The rejection region is area > 1.319

c) Ha: μ > 10

This is a right tailed test

n = 99

α = 0.05

We would reject the null hypothesis if the test statistic is greater than the table value of 1 - α

1 - α = 1 - 0.05 = 0.95

The critical value is 1.66

The rejection region is area > 1.66

d) Ha: μ < 10

This is a left tailed test

n = 11

α = 0.1

We would reject the null hypothesis if the test statistic is lesser than the table value of 1 - α

1 - α = 1 - 0.1 = 0.9

The critical value is 1.363

The rejection region is area < 1.363

e) H0: μ = 10

Ha: μ ≠ 10

This is a two tailed test

n = 20

Since α = 0.05, we would find the critical value corresponding to 1 - α/2 and reject the null hypothesis if the absolute value of the test statistic is greater than the value of t 1 - α/2 from the table.

1 - α/2 = 1 - 0.05/2 = 1 - 0.025 = 0.975

The critical value is 2.086

The rejection region is area > 2.086

f) Ha: μ < 10

This is a left tailed test

n = 77

α = 0.01

We would reject the null hypothesis if the test statistic is lesser than the table value of 1 - α

1 - α = 1 - 0.01 = 0.99

The critical value is 2.376

The rejection region is area < 2.376

7 0
3 years ago
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