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SOVA2 [1]
3 years ago
9

Please i know people find this stuff easy but i dont i need to find the SSS SAS AAS or HL

Mathematics
1 answer:
BaLLatris [955]3 years ago
8 0

Answer:omh

Step-by-step explanation:

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Suppose a solid is formed by revolving the function f(x)=2+mx around the x-axis where 0≤m&lt;1 and 0≤x≤1, and a washer is create
BabaBlast [244]

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(m³/3 + 5m/2 + 3)pi

Step-by-step explanation:

pi integral [(f(x))² - (g(x))²]

Limits 0 to 1

pi × integral [(2+mx)² - (1-mx)²]

pi × integral[4 + 4mx + m²x² - 1 + 2mx - m²x²]

pi × integral [m²x² + 5mx + 3]

pi × [m²x³/3 + 5mx²/2 + 3x]

Upper limit - lower limit

pi × [m²/3 + 5m/2 + 3]

Verification:

m = 0

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[m³/3 + 5m/2 + 3]pi

m = 0

3pi

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3 years ago
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