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ololo11 [35]
3 years ago
7

I need help please thank you :)

Mathematics
1 answer:
My name is Ann [436]3 years ago
6 0

Answer:ABD

Step-by-step explanation:all of them are less than 1 which means it is discounted

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370 College freshmen were interviewed. 200 were registered for an Advanced Math class. 270 were registered for an English class
frozen [14]

Answer:

Step-by-step explanation:

To aid in understanding, draw three circles...

100 were registered for both Math and English.

50 were registered for both Sport and English but not Math.

70 were registered for Math, Sport, and English.

From here we will be able to calculate for those that signed up for only English class: Total number of students that signed up for english class

a. none signed up only for Maths (refer to attached document)

b. How many signed up for neither Math nor English meaning they signed up for only sports which is 70 from the venn diagram in the attachment.

c. How many signed up for an English class and at least one other class?

From the venn diagram:

we could have an English class and maths class - 100

we could also have an a English class and sports - 50

Thus total is 150.

d. What is the total fee for all the students enrolled in classes

From the diagram, 120 (english only and sport only) enrolled for only one class = 120 x $100 = $12,000

From the diagram, 180 (english and sport, maths and sport and english and maths) enrolled for two classes = 180 x $150 = $27,000

From the diagram, only 70 enrolled for the three classes = 70 x $200 = $14,000

Total fees = $12,000 + $27,000 + $14,000 = $53,000

5 0
4 years ago
Can someone please help me
amid [387]
She has 6 on Wednesday
Since we know that she has 4/9 left, 4/9 of 27 is 12. So she has 12 on Tuesday. Now 2/4 or 1/2 is left on Wednesday. Half of 12 is 6. So she has 6 left
8 0
3 years ago
Read 2 more answers
Please use the photo and do the prove for #13 because I’m having a really hard time. Thanks!
rewona [7]

∠2 = ∠3 | Given

∠1 + ∠2 = 180 | Supplementary Angles Postule (If two angles are adjacent and                  ∠3 + ∠4 = 180|                                                        linear, they're supplementary)

∠1 + ∠2 = ∠3 + ∠4 | Transitive property

∠1 + ∠3 = ∠3 + ∠4 | Substitution property

∠1 = ∠4 | Subtraction Property

∠2 = ∠3 | Supplementary Congruent Theorem

7 0
3 years ago
100 POINTS AND BRAINLIYEST!!!
Helga [31]

See explanations below

Step-by-step explanation:

Chanel

(i) 90° counterclockwise and then dilation by a factor of 1/2

Trapezoid PQRS is given as :

P(6,-4) -------P'(4,6)

Q(2,-2)------Q'(2,2)

R(2,-6)-------R'(6,2)

S(6,-6)-------S'(6,6)

The transformation switches the position of (x,y) to and adds a -ve sign to the original y value

B. The new coordinates are : P'(4,6), Q'(2,2),R'(6,2) and S'(6,6)

The  rule for rotation 90° counterclockwise about the origin is (x,y)⇒(-y,x)

The rule for dilation with scale factor of 1/2 is (x,y)------(1/2x,1/2y)

P'(4,6) -----P''(2,3)

Q'(2,2)-----Q''(1,1)

R'(6,2)-----R''(3,1)

S'( 6,6)-----S''(3,3)

The dilation reduces the coordinates by 1/2

Preston

E. (i)Reflection over x-axis where the rule is : (x,y)----(x,-y)

(ii)Dilation by scale factor of 1/2 the rule is : (x,y)---(1/2x, 1/2y)

Applying reflection over x-axis rule;

P(6,-4) -----P'(6,4)

Q(2,-2)-----Q'(2,2)

R(2,-6)------R'(2,6)

S(6,-6)------S'(6,6)

The coordinates have changed in that a negative sign is added to the y-axis coordinate.

F. P'(6,4), Q'(2,2), R'(2,6) and S'(6,6)

G. Applying the dilation by scale factor of 1/2

P'(6,4)-------P''(3,2)

Q'(2,2)------Q''(1,1)

R'(2,6)------R''(1,3)

S'(6,6)------S''(3,3)

The coordinates of P'Q'R'S are divide by 2 to give coordinates of P''Q''R''S''

Comparing the answers to the final figure given

K(3,2)

L(1,1)

M(1,3)

N(3,3)

Preston is correct because his sequence proves trapezoid PQRS is similar to trapezoid KLMN.

Learn More

Reflection and dilation :brainly.com/question/13408902

Keywords :trapezoid, maps, rotate, counterclockwise, dilate,reflect,scale factor,shape, coordinate

#LearnwithBrainly

4 0
3 years ago
Read 2 more answers
How can you represent the system of equations with a matrix?<br><br> 11x - 12y = 7<br> 5x + 12y = -7
kirza4 [7]
Take the linear coefients easy

11,-12, 7
5,12,-7
so

\left[\begin{array}{ccc}11&-12&7\\5&12&-7\end{array}\right] or you could do also
\left[\begin{array}{ccc}11&-12\\5&12\end{array}\right]   \left[\begin{array}{ccc}7\\-7\end{array}\right]
5 0
3 years ago
Read 2 more answers
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