Well I think I can help you out ...
if you assume input x=2
the output will be as following :
y= -1/3(2)+2
=-2/3+2
=-2/3+6/3
=(-2+6)/3
=4/3
=1.333
Answer:
5/3
Step-by-step explanation:
use the rise/run tactic
Answer:
5,5
Step-by-step explanation:
down right boom bam (-5,5)
Hey!
![-6(2x-5) = 18](https://tex.z-dn.net/?f=%20-6%282x-5%29%20%3D%2018%20)
Switch it around and it becomes:
![2x - 5 = 18 \div -6](https://tex.z-dn.net/?f=%202x%20-%205%20%3D%2018%20%5Cdiv%20-6%20)
First find 18 ÷ -6
![18 \div -6 = -3](https://tex.z-dn.net/?f=%2018%20%5Cdiv%20-6%20%3D%20-3%20)
Positive ÷ negative OR negative ÷ positive is always negative.
That leaves you with:
![2x - 5 = -3](https://tex.z-dn.net/?f=%202x%20-%205%20%3D%20-3%20)
Switch that around and it becomes:
![-3 + 5 = 2x](https://tex.z-dn.net/?f=%20-3%20%2B%205%20%3D%202x%20)
Find -3 + 5
![-3 + 5 = 2](https://tex.z-dn.net/?f=%20-3%20%2B%205%20%3D%202%20)
That leaves you with:
![2 = 2x](https://tex.z-dn.net/?f=%202%20%3D%202x%20)
Divide both sides by 2 to leave <em>x</em> alone
![\frac{2}{2} = \frac{2x}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B2%7D%20%3D%20%20%5Cfrac%7B2x%7D%7B2%7D%20%20)
![\framebox{x = 1}](https://tex.z-dn.net/?f=%20%5Cframebox%7Bx%20%3D%201%7D%20)