Answer:
i believe it is 57
Step-by-step explanation:
since complimentary angles add up to 90 and angle 1 is 33 if you were to subtract 33 from 90 you would get 57
Step-by-step explanation:
6a + 7 -(4a+3) original problem
6a + 7 - 4a - 3 distributive property
6a - 4a + 7 - 3 combining like terms
2a + 4 simplified form
I hope this helps!!!
I believe this is it.
x is Coleman's test grade.
x/2 +27 = 67 Now solve for x
-27 -27
x/2=40
*2 *2
x=80
Coleman's Test Score was 80.
Answer: 15/28
Suppose the following:
event A: the event that there were 3 sixes in the 8 roles,
event B: the event that there were 2 sixes in the first 5 roles.
Then the conditional probability to find is P(B|A)=P(A∩B)/P(A).
P(A)=C(3,8)*(1/6)^3*(5/6)^5,
P(A∩B)=C(2,5)*(1/6)^2*(5/6)^3*C(1,3)*(1/6)*(1/6)^2
∴P(B|A)=15/28
Answer:
102 nickels and 56 quarters
Step-by-step explanation:
Since the total amount of coins is 158, then...
q+n=158
Since the total amount of money is $19.10, and a quarter is 25 cents and a nickel is 5 cents, then...
0.25q+0.05n=19.10
Now that we have 2 equations and 2 variables, we can solve for this equation by solving the first equation for q and plugging it into the second equation.
q+n=158,
q=158-n
Plug into the other equation,
0.25(158-n)+0.05n=19.10
and solve for n
39.5-0.25n+0.05n=19.10
39.5-0.2n=19.10
-0.2n=-20.4
n=102
there are 102 nickels.
Now solve for quarters.
q+n=158
q+102=158
q=158-102
q=56