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2 years ago

A) 9 to the power of minus 1 over 2 (9^-1/2) b) 27 to the power of minus 2 over 3 (27^-2/3)

Mathematics

1 answer:

ella [17]2 years ago

4 0

Step-by-step explanation:

a) 9^-½

= (1/9)^½

= (√1)/(√9)

= 1/3

=0.333....

b). 27^-⅔

= (1/27)^⅔

=(³√1)²/(³√27)²

=1/9

=0.111.....

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3 years ago

Why is it helpful to rewrite inequalities

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It isn't always.

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So, for an inequality, that puts the variable on the left:

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3 years ago

A coin bank that excepts only nickels and dimes contains $9.15. There are three more than twice as many nickels as there are dim

valentinak56 [21]

45 dimes and 93 nickels were in bank

<em><u>Solution:</u></em>

Let "n" be the number of nickels

Let "d" be the number of dimes

We know that,

value of 1 nickel = $ 0.05

value of 1 dime = $ 0.10

<em><u>Given that There are three more than twice as many nickels as there are dimes</u></em>

Number of nickels = 3 + 2(number of dimes)

n = 3 + 2d ---- eqn 1

<em><u>Also given that coin bank that excepts only nickels and dimes contains $9.15</u></em>

number of nickels x value of 1 nickel + number of dimes x value of 1 dime = 9.15

$n \times 0.05 + d \times 0.10 = 9.15$

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<em><u>Let us solve eqn 1 and eqn 2</u></em>

Substitute eqn 1 in eqn 2

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