Answer:
Step-by-step explanation:
Let q represent the number of quarters Theresa has. Then the value of her coins is ...
0.25q + 0.10(20 -q) = 2.75
0.15q = 0.75 . . . . . . . . . subtract 2.00, collect terms
q = 0.75/0.15 = 5
Theresa has 5 quarters and 15 dimes.
Answer:
Step-by-step explanation:
Let n = the smaller of the two numbers, and since the other number is 5 more than twice the smaller number n, then ...
Let 2n + 5 = the second and larger number.
Since the sum of the two unknown numbers is 26, then we can write the following equation to be solved for n as follows:
n + (2n + 5) = 26
n + 2n + 5 = 26
Collecting like-terms on the left, we get:
3n + 5 = 26
3n + 5 - 5 = 26 - 5
3n + 0 = 21
3n = 21
(3n)/3 = 21/3
(3/3)n = 21/3
(1)n = 7
n = 7
Therefore, ...
2n + 5 = 2(7) + 5
= 14 + 5
= 19
CHECK:
n + (2n + 5) = 26
7 + (19) = 26
7 + 19 = 26
26 = 26
Therefore, the two desired numbers whose sum is 26 are indeed 7 and 19.
Trapezoid:
•Can have congruent diagonals. •Has one pair of opposite, parallel sides.
Kites:
•Has congruent adjacent sides.
•Has perpendicular diagonals.
Answer:
0.75
Step-by-step explanation:
3/4=0.75
Hope this helps! :)
