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3 years ago

14

Need help on this volume/surface area

1 answer:

Vinil7 [7]3 years ago

3 0

8. Answer:

Imagine opening the Triangular prism

We will have 2 triangles at the base

and 3 rectangles

The sides of the triangle : base 9in, height 3in

Area of Triangle

= $\frac{1}{2} * base * height = \frac{1}{2} * 9*3 =\frac{27}{2}$

Now the rectangles

Rectangle1 with sides 9in and 15in, Area = 9*15 = 135

Rectangle 2 with sides 5in and 15in , Area = 5*15 = 75

Rectangle 3 with sides 6in and 15in, Area = 6*15 = 90

Now the total area of the prism

= $\frac{27}{2}+\frac{27}{2}+135+75+90 = 27+ 135+75+ 90 = 327in^{2}$

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asambeis [7]

Answer:

3×(3×7)

Step-by-step explanation:

Just move the perenthasies to the right

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3 years ago

Read 2 more answers

the wholesale price for a pair of shoes is $5.50. A certain department store marks up the wholesale price by 40%. Find the price

Furkat [3]

EXPLANATION

Price of shoes = $5.50

Markup= 40%

Let's call x to the unknown final price.

The markup percentage relationship is given by the following formula:

$\text{Markup =( }\frac{Selling\text{ Price}-\text{Cost Price}}{\text{Cost Price}})\cdot100$

Replacing terms:

$\text{40}=(\frac{x-5.5}{5.5})\cdot100$

Multiplying both sides by 5.5:

$40\cdot5.5=(x-5.5)\cdot100$

Dividing both sides by 100:

$\frac{40\cdot5.5}{100}=x-5.5$

Adding 5.5 to both sides:

$(\frac{40\cdot5.5}{100})+5.5=x$

Simplifyng the fraction:

$2.2+5.5=x$

Adding numbers:

$\text{7}.7\text{ = x}$

Switching sides:

$x=7.7$

Answer: The final price of the shoes in the deparment store is $7.7

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1 year ago

What Is Tan B?<br><br> need help asap!

andrew-mc [135]

Answer:

Try looking it up on a search engine and you might find the answer

Step-by-step explanation:

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3 years ago

N 4n3 2m 6m 5n 2n<br> Identify like terms

Juliette [100K]

Answer:

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4n3

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3 years ago

Anyone help me. ....

weeeeeb [17]

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

All the exponents inside the parenthesis are multiplied by the exponent outside the parenthesis.

Then

$\frac{m^{-7}n^{14} }{m^{-25}n^{40} }$ ÷ $\frac{m^{-21}n^{42} }{m^{-25}n^{40} }$

[ Using the rule $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ ]

= $m^{(-7-14)}$ $n^{(14-(-28)}$ ÷ $m^{(-15-10)}$ $n^{(25-(-15)}$

= $m^{-21}$ $n^{14+28}$ ÷ $m^{-25}$ $n^{25+15}$

= $\frac{m^{-21}n^{42} }{m^{-25}n^{40} }$

= $m^{(-21-(-25))}$ $n^{(42-40)}$

= $m^{(-21+25)}$ n²

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Then

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3 years ago