Answer:
pyramid with triangular base
From the given function modeling the height of the ball:
f(x)=-0.2x^2+1.4x+7
A] The maximum height of the ball will be given by:
At max height f'(x)=0
from f(x),
f'(x)=-0.4x+1.4
solving for x we get:
-0.4x=-1.4
x=3.5ft
thus the maximum height would be:
f(3.5)=-0.2(3.5)^2+1.4(3.5)+7
f(3.5)=9.45 ft
b]
How far from where the ball was thrown did this occur:
from (a), we see that at maximum height f'(x)=0
f'(x)=-0.4x+1.4
solving for x we get:
-0.4x=-1.4
x=3.5ft
This implies that it occurred 3.5 ft from where the ball was thrown.
c] How far does the ball travel horizontally?
f(x)=-0.2x^2+1.4x+7
evaluationg the expression when f(x)=0 we get:
0=-0.2x^2+1.4x+7
Using quadratic equation formula:
x=-3.37386 or x=10.3739
We leave out the negative and take the positive answer. Hence the answer 10.3739 ft horizontally.
The base of the exponential function must be a positive number, then option C. it's not possible.
In the graph, when x=0, y=3
Option B it's not posiible because when x=0→F(0)=3^0→y=1
In the graph, when x=1, y is approximately 4
Option A it's not possible because when x=0→F(0)=3*(0.4)^1=3*0.4→y=1.2
It's option D, because when x=0→F(0)=3*(1.4)^1=3*1.4→y= 4.2
Answer: OPtion D. F(x)=3*(1.4)^x
Answer:
(-9/2,3/2)
Step-by-step explanation:
x coordinate of mid point=(x1+x2)/2
y coordinate of mid point=(y1+y2)/2
