Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
Firstly, I noticed that there are fractions, decimals, and percents. I will change everything to percents, so it’s more easy for me to compare each of them.
List 1. 140%, 25%, 14%. This is from greatest to least, not least to greatest.
List 2. 25%, 14%, 14%. This is not from least to greatest, either.
List 3. 14%, 25%, 140%. This is from least to greatest.
List 4. 140%, 14%, 25%. This is not from least to greatest.
List 3 is from least to greatest. I got this answer by converting all of the fractions and decimals to percentages.
Answer:
8.245*10^6
Step-by-step explanation:
scientific notation is known as c*10^n
c : any number from 1-10
n : the power of base 10
the number in our case between 1 and 10 is 8.245
but then we want to move the decimal 6 spaces to the right, so we multiply that by 10^6
2 - 12 + 18
= -10 + 18
= 8
The answer is D.
1303/12.8 is the answer for that one which it should land in the middle of the line!
