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d1i1m1o1n [39]
3 years ago
5

345.2-126.4+712.4x634.4

Mathematics
1 answer:
scoundrel [369]3 years ago
8 0
452,165.36 ? That should be the answer lol
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The answer is 69.45
hope this helps :)
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3 years ago
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Whats 2 + 3 + 5 + 6 please help
Ratling [72]

Answer:

16

Step-by-step explanation:

2+3=5+5=10+6=16 i cant tell if this is a joke but oh well ‍♀️

4 0
3 years ago
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I'm reasking a previous question to make it more clear. This is a Linear Equation that I must solve. It includes fractions (the
Ugo [173]

Assuming the equation is:

\frac{x}{2}-\frac{10x-25}{10}=3(x+3)-(x-14)


When fractions involve numeric denominators, the fractions can be removed by multiplying (both sides) by the LCM of the denominators.


Here the denominators are 2 and 10, hence the LCM is 10.


Multiply by 10 on both sides, not forgetting to distribute when multiplying on the right side:

10\frac{x}{2}-10\frac{10x-25}{10}=10*3(x+3)-10(x-14)

simplify, remember that there are always implied parentheses around numerators and denominators:

5x-(10x-25)=30(x+3)-10(x-14)

Now, distribute, i.e. remove parentheses and distribute:

5x-10x+25=30x+90-10x+140

Simplify

-5x+25=20x+230

transpose terms

25-230=20x+5x

solve

x=-205/25=-41/5


In this particular case, we can also take advantage of the term

(10x-25)/10=5(2x-5)/10=(2x-5)/2 which greatly simplifies the solution process, because the LCM will then be 2 instead of 10.

If we do that, the solution will be:

Multiply by 2 on both sides, not forgetting to distribute when multiplying on the right side:

\frac{x}{2}-\frac{10x-25}{10}=3(x+3)-(x-14)

simplify, remember that there are always implied parentheses around numerators and denominators:

2\frac{x}{2}-2\frac{2x-5}{2}=2*3(x+3)-2(x-14)

x-(2x-5)=6(x+3)-2(x-14)

Now, distribute, i.e. remove parentheses and distribute:

x-2x+5=6x+18-2x+28

Simplify

-x+5=4x+46

solve

5-46=4x+x

-41=5x

x=-41/5

with the same results.

7 0
4 years ago
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Round 17 5/8 to the nearest whole number
Greeley [361]
18 is the nearest whole number
7 0
4 years ago
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Solve the system of equations.
nadya68 [22]

Answer:

using the first two equations cancelling the z

-2x-2y-5z=-7

6x+8y+5z=9

4x +6y= 2

using the second and the third equations cancelling the z

6x+8y+5z= 9

-2x-3y-5z= -6

4x +5y = 3

4x + 6y = 2

-4x -5y = -3

y= -1

2x + 2(-1) + 5z = 7

2x - 2 + 5z = 7

2x + 5z = 9

6x + 8(-1) + 5z = 9

6x - 8 + 5z = 9

6x + 5z = 17

-2x - 5z= -9

4x = 8

x = 2

2(2) + 2(-1) + 5z= 7

4 - 2 + 5z = 7

2 + 5z = 7

5z = 5

z = 1

(2, -1, 1)

the answer is a.

Step-by-step explanation:

3 0
4 years ago
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