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mixer [17]
3 years ago
13

Simplify the expression (x-4)( x-7) + (3-x)(2+x). PLEASE HELPPPPP!

Mathematics
2 answers:
Effectus [21]3 years ago
8 0

Answer:

-10x +34

Step-by-step explanation:

$(x-4)(x-7)$

(x-4)(x-7) &= x(x-7) - 4(x-7)\\

&=x^2 - 7x -4x +28\\

&=x^2 - 11x + 28.

$(3-x)(2+x)$

(3-x)(2+x) &= 3(2+x) - x(2+x)\\

&=6 + 3x - 2x - x^2\\

&= 6+x -x^2.

(x-4)(x-7) + (3-x)(2+x) &= (x^2 - 11x + 28) + (6+x-x^2)\\

&= (x^2 - x^2) + (-11x + x) + (28 + 6)\\

=-10x + 34

ddd [48]3 years ago
7 0
(x^2-11x+28)(6-x-x^2)2x^2 - 12x + 34
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Answer:

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Step-by-step explanation:

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Since, the numerator of the number 9÷0.001 is greater than 8÷0.001. and as their denominator is same.

so, the number whose numerator is greater than the other will result in the overall number to be greater.

  • The division expression which is less than 8÷0.001 is 7÷0.001.

Since, for two numbers with same denominator the number whose numerator is smaller is smaller than the other.

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Since 8÷0.002 is greater than 8÷110, as for two numbers with same numerator but different denominator the number whose denominator is greater is a smaller number.

similarly 8÷0.002 is smaller than 8÷0.001.





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3 years ago
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