Answer:
75=2x-13
75+13=2x-13+13
88=2x
88÷2=2x÷2
44=x
Step-by-step explanation:
Answer:
x = 5 units.
Step-by-step explanation:
In a parallelogram. diagonals bisect each other.
This means
.


.
Therefore, the length of x = 5 units.
Answer:
15 rooms
Step-by-step explanation:
1:$32 = x:$500
$32×x = 1×$500
x = $500/$32
x = 15, 625
namely, how many times does 0.4 go into 6⅓? or 6⅓ ÷ 0.4.
first off, let's convert the mixed fraction to improper, and the decimal to a fraction . We can always convert the decimal to a fraction by simply <u>adding as many zeros on the denominator as there are decimals and lose the dot atop</u>, let's do so.
![\bf 0.\underline{4}\implies \cfrac{04}{1\underline{0}}\implies \cfrac{4}{10}\implies \cfrac{2}{5}~\hfill \stackrel{mixed}{6\frac{1}{3}}\implies \cfrac{6\cdot 3+1}{3}\implies \stackrel{improper}{\cfrac{19}{3}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{How many servings of pasta were in the dish?}}{6\frac{1}{3}\div 0.4\implies \cfrac{19}{3}\div \cfrac{2}{5}}\implies \cfrac{19}{3}\cdot \cfrac{5}{2}\implies \cfrac{95}{6}\implies 15\frac{5}{6}](https://tex.z-dn.net/?f=%5Cbf%200.%5Cunderline%7B4%7D%5Cimplies%20%5Ccfrac%7B04%7D%7B1%5Cunderline%7B0%7D%7D%5Cimplies%20%5Ccfrac%7B4%7D%7B10%7D%5Cimplies%20%5Ccfrac%7B2%7D%7B5%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B6%5Cfrac%7B1%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7B6%5Ccdot%203%2B1%7D%7B3%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B19%7D%7B3%7D%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A%5Cstackrel%7B%5Ctextit%7BHow%20many%20servings%20of%20pasta%20were%20in%20the%20dish%3F%7D%7D%7B6%5Cfrac%7B1%7D%7B3%7D%5Cdiv%200.4%5Cimplies%20%5Ccfrac%7B19%7D%7B3%7D%5Cdiv%20%5Ccfrac%7B2%7D%7B5%7D%7D%5Cimplies%20%5Ccfrac%7B19%7D%7B3%7D%5Ccdot%20%5Ccfrac%7B5%7D%7B2%7D%5Cimplies%20%5Ccfrac%7B95%7D%7B6%7D%5Cimplies%2015%5Cfrac%7B5%7D%7B6%7D)
Since you're told c is the independent varialbe, you need to solve your equation for p:
6c = 2p - 10
6c + 10 = 2p
3c + 5 = p
Now you need to use function notation. Remember that in function notation, you need to use the variable consistently.
f(p) = something with c doesn't match up.
You need
f(c) = something with c in it
Even without doing the first initial work, the only answer that makes c the independent variable is <u>Answer B</u>. But it's also good that <u>Answer B</u> matches our equation above.