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3 years ago

6

A construction crew is lengthening a road that originally measured 52 miles. The crew is adding one mile to the road each day. T

he length, L (in miles), after
d days of construction is given by the following.
L=52+d
N
What is the length of the road after 36 days?

1 answer:

kramer3 years ago

6 0

?=52+36=88 miles long

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A website received 2500 registered members in July. And the number of registered members in August decreased to 2245. What was t

quester [9]

Number of registrations a website received during July = 2500

Number of registrations a website received during August = 2245

Number by which the registrations decreased :

$=\tt 2500 - 2245$

$=\tt 255$

Thus, the registrations decreased by 255.

Let x be the perrcentage of decrease.

Which means :

$=\tt 255 = \frac{x}{100} \: of \: 2500$

$= \tt255 = \frac{x \times 2500}{100}$

$=\tt 255 = \frac{2500x}{100}$

$= \tt255 \times 100 = 2500x$

$= \tt25500 = 2500x$

$=\tt \frac{25000}{2500} = x$

$\color{plum} =\tt \bold{10.2\%}$

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3 years ago

How can you use doubles when multiplying with 4 to find 4x8

pshichka [43]

4 = 2 * 2

Multiplying by 2 is the same a doubling.
Since 4 is 2 * 2, to multiply a number by 4, double the number twice.

Example:
What is 4 * 100?
Double 100 to get 200.
Double 200 to get 400.
Therefore, 4 * 100 = 400.
By doubling twice, we do the same as multiplying by 4.

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3 years ago

7/2x + 1/2x + 5 1/2 + 92x <br> the value of x is..

jeka94

I'm not entirely sure what you mean but simplifying this expression results in 96x + 5 1/2.

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3 years ago

A rectangular box has a square base. The combined length of a side of the square base, and the height is 20 in. Let x be the len

aniked [119]

Answer:

a. V = (20-x) $x^{2}$ $in^{3}$

b . 1185.185 $in^{3}$

Step-by-step explanation:

Given that:

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Let x be the length of a side of the base of the box (x>0)

a. Write a polynomial function in factored form modeling the volume V of the box.

As we know that, this is a rectangular box has a square base so the Volume of it is:

V = h * $x^{2}$ $in^{3}$

<=> V = (20-x) $x^{2}$ $in^{3}$

b. What is the maximum possible volume of the box?

To maximum the volume of it, we need to use first derivative of the volume.

<=> dV / Dx = -3 $x^{2}$ + 40x

Let dV / Dx = 0, we have:

-3 $x^{2}$ + 40x = 0

<=> x = 40/3

=>the height h = 20/3

So the maximum possible volume of the box is:

V = 20/3 * 40/3 *40/3

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3 years ago

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Let's try the actual solution of the system

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</span>

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