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3 years ago

What is the other measure of the other acute angle? Pls explain how you got your answer !

Mathematics

1 answer:

Anastasy [175]3 years ago

3 0

Answer:

$65^{o}$

Step-by-step explanation:

Angles in a triangle add up to 180

An acute angle is any angle smaller than 90

Since it is a right angle triangle, one of the angles is a right angle and therefore 90

So 180 - 90 - 25 = 65

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A geologist gathered data about the total shoreline and maximum depth of several area lakes and organized the data into this tab

givi [52]

Answer: D. 143

Step-by-step explanation:

31 times 4.26 = 132.06 + 10.908 = 142.968 which simplifies to 143 because you round up.

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3 years ago

I need help with Precal asap !!!! I’ll mark u as brainliest, please if you don’t know the correct answer don’t write down.

Amanda [17]

Answer:

Equation 1: r = 4 +( 3 * cos theta )

Equation 2: r = sqrt ( 5² * sin(2 theta) )

Step-by-step explanation:

GRAPH 1:

The first graph is a dimpled limacon.

General equation for dimpled limacon:

r = a + b cos theta ∴ if dimple is along the x- axis

r = a + b sin theta ∴ if dimple is along the y-axis

y-intercept : { a, -a } = { 4, -4 } ∴ the points at which limacon intersects y-axis

Negative side of x-axis = ( a – b ) ⇒ 1

Positive side of x-axis = ( a + b ) ⇒ 7

Subtract the value of a from sum of a and b to find b:

b = 7 – 4 ⇒ 3

Equation1: r = 4 +( 3 * cos theta )

GRAPH 2:

The second graph is a lemniscates.

General equation for lemniscates is:

r² = a² cos(2theta) ∴ if petals of graph are on coordinate axis

r² = a² sin(2 theta) ∴ if petals of graph are not on coordinate axis

now, according to the graph:

a = 5 ⇒ a² = 25

angle of graph: cos2θ, simply divide 360° by 2:

$\frac{360}{2}$ ⇒ 180°

The petals cannot be on coordinate axis, we start from 45° and then the next petal will be on:

45° + 180° = 225°

Since the graph is not on the coordinate axis, so

r² = 5² sin(2 theta) ⇒ r = sqrt ( 5² * sin(2 theta) )

Equation 2: r = sqrt ( 5² * sin(2 theta) )

6 0

3 years ago

Write the following expression in words x+7

Lady_Fox [76]

Answer:

The sum of 7 and x.

Step-by-step explanation:

PLS GIVE BRAINLIEST

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3 years ago

Solve |x|>5 A. {-5,5} B. { x|-5 < x < 5 } C. { x|x < -5 or x > 5}

Marizza181 [45]

Solve |×|> 5

×>5 or ×<-5

C.{×<-5 or ×> 5}

8 0

3 years ago

An equilateral triangle is inscribed in a circle of radius 6r. Express the area A within the circle but outside the triangle as

Paul [167]

Answer:

$A(x)=\frac{100\pi x^2-75\sqrt{3}x^2}{12}$

Step-by-step explanation:

We have been given that an equilateral triangle is inscribed in a circle of radius 6r. We are asked to express the area A within the circle but outside the triangle as a function of the length 5x of the side of the triangle.

We know that the relation between radius (R) of circumscribing circle to the side (a) of inscribed equilateral triangle is $\frac{a}{\sqrt{3}}=R$ .

Upon substituting our given values, we will get:

$\frac{5x}{\sqrt{3}}=6r$

Let us solve for r.

$r=\frac{5x}{6\sqrt{3}}$

$\text{Area of circle}=\pi(6r)^2=\pi(6\cdot \frac{5x}{6\sqrt{3}})^2=\pi(\frac{5x}{\sqrt{3}})^2=\frac{25\pi x^2}{3}$

We know that area of an equilateral triangle is equal to $\frac{\sqrt{3}}{4}s^2$ , where s represents side length of triangle.

$\text{Area of equilateral triangle}=\frac{\sqrt{3}}{4}s^2=\frac{\sqrt{3}}{4}(5x)^2=\frac{25\sqrt{3}}{4}x^2$

The area within circle and outside the triangle would be difference of area of circle and triangle as:

$A(x)=\frac{25\pi x^2}{3}-\frac{25\sqrt{3}x^2}{4}$

We can make a common denominator as:

$A(x)=\frac{4\cdot 25\pi x^2}{12}-\frac{3\cdot 25\sqrt{3}x^2}{12}$

$A(x)=\frac{100\pi x^2-75\sqrt{3}x^2}{12}$

Therefore, our required expression would be $A(x)=\frac{100\pi x^2-75\sqrt{3}x^2}{12}$ .

7 0

3 years ago