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Sergio039 [100]
3 years ago
7

Determine the products of the decimals 4.5 • 3

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
7 0

Answer: 13.5

Step-by-step explanation: multiply the two numbers

SVETLANKA909090 [29]3 years ago
3 0

Answer:

13.5

Step-by-step explanation:

put into calculator

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PLEASE HELP IMMEDIATELY
Paha777 [63]
The answer is g = 6w.

since the number of grey pigeons is 6 times the white pigeons, it means the white pigeons are being multiplied to find the number of grey pigeons
3 0
3 years ago
Help and explain pls
Lina20 [59]

Answer: are they asking for the answer of the dotted line? If so, it might be 5 since it's the dotted line is opposing the side labeled 5cm.

Hope this helps:)

Step-by-step explanation:

5 0
3 years ago
A Martian couple has children until they have 2 males (sexes of children are independent). Compute the expected number of childr
Ne4ueva [31]

Answer:

a) 6

b) 4

c) 3

Step-by-step explanation:

Let p be the probability of having a female Martian, and of course, 1-p the probability of having a male Martian.

To compute the expected total number of trials before 2 males are born, imagine an experiment simulating the fact that 2 males are born is performed n times.

Let ak be the number of trials performed until 2 males are born in experiment k. That is,

a1= number of trials performed until 2 males are born in experiment 1

a2= number of trials performed until 2 males are born in experiment 2

and so on.

If a1 + a2 + … + an = N

we would expect Np females.  

Since the experiment was performed n times, there 2n males (recall that the experiment stops when 2 males are born).

So we would expect 2n = N(1-p), or

N/n = 2/(1-p)

But N/n is the average number of trials per experiment, that is, the expectation.

<em>We have then that the expected number of trials before 2 males are born is 2/(1-p) where p is the probability of having a female. </em>

a)

Here we have the probability of having a male is half as likely as females. So

1-p = p/2 hence p=2/3

The expected number of trials would be

2/(1-2/3) = 2/(1/3) =6

This means <em>the couple would have 6 children</em>: 4 females (the first 4 trials) and 2 males (the last 2 trials).

b)

Here the probability of having a female = probability of having a male = 1/2

The expected number of trials would be

2/(1/2) = 4

This means<em> the couple would have 4 children</em>: 2 females (the first 2 trials) and 2 males (the last 2 trials).

c)

Here, 1-p = 2p so p=1/3

The expected number of trials would be

2/(1-1/3) = 2/(2/3) = 6/2 =3

This means<em> the couple would have 3 children</em>: 1 female (the first trial) and 2 males (the last 2 trials).

5 0
3 years ago
How many times does 15 goes into 2
Whitepunk [10]

Answer:

7

Step-by-step explanation:

2,4,6,8,10,12,14 that is howni got my answer

4 0
3 years ago
Read 2 more answers
1.The coordinates of the vertices of △RST are R(−4, −1) , S(−1, −1) , and T(−4, −2) .
Tju [1.3M]

RS points east; R'S' points north, so there has been a rotation 90° CCW.

After that rotation, point S would be at (1, -1). It is actually at (1, 1), so has been shifted 2 units upward.

A sequence that does the desired mapping is

  • c. rotation of 90° CCW about the origin
  • b. translation 2 units up

8 0
3 years ago
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