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Nady [450]
3 years ago
10

Mean median mode and range,4,8,6,4,4,1,1

Mathematics
1 answer:
Artist 52 [7]3 years ago
5 0
Mean: 4 [(4+8+6+4+4+1+1)/7]

median: 4 [1 1 4 4 4 6 8 the number in the middle is 4

mode: 4 [ there are 3 fours which is the most out of all the numbers]

range: 7 [8-1=7]
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Reduce to simplest form.<br> -7/12 +3/8
faust18 [17]

Answer:

-5/24

Step-by-step explanation:

here u gooo :).....

4 0
3 years ago
I need help with this and please show your work
Nikolay [14]
5 1/6 * (-2/5) = __
turn 5 1/6 into a mixed fraction
31/6 * (-2/5) = __
multiply
31 * -2 = -62
6 * 5 = 30
so -62/30 or -2 1/15
Hopefully the attachment helps too!

5 0
3 years ago
Help please math ..??
astraxan [27]

Answer:

(3, - 1)

Step-by-step explanation:

5x - 4y = -11

2x + 3y = -9

Multiply the top equation by 2 and the bottom equation by - 5 to cancel out the x's.

10x - 8y = - 22

- 10x - 15y = 45

Cancel out x's.

-8y = - 22

- 15y = 45

Add like terms.

- 23y = 23

Can't have a negative variable to flip them.

-23 = 23y

Divide.

y = - 1

Input y into one of the equations and solve for x.

2x + 3(-1) = -9

Simplify.

2x -3 = -9

Cancel out -3 by adding 3.

2x = -6

Divide.

x - -3

8 0
3 years ago
Find r if (r, 6) and (5, -4) are two points on a line with a slope of 5/7 (Hint: use the slope formula)
andreyandreev [35.5K]

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have

(r,\ 6),\ (5,\ -4)\\\\m=\dfrac{5}{7}

Substitute

\dfrac{-4-6}{5-r}=\dfrac{5}{7}\\\\\dfrac{-10}{5-r}=\dfrac{5}{7}\qquad|\text{cross multiply}\\\\5(5-r)=(-10)(7)\qquad|\text{use distributive property}\\\\25-5r=-70\qquad|-25\\\\-5r=-95\qquad|:(-5)\\\\\boxed{r=19}

4 0
3 years ago
Please help pls pls help pls belp
Delvig [45]

Answer:

After 1 second, the ball will reach a maximum height of 16 feet

Step-by-step explanation:

The height of the ball after t seconds: h(t) = -16t^2 + 32t

The graph of this quadratic function is parabola which opens downwards. The vertex of a quadratic equation is the maximum or minimum point on the equation's parabola

t = -b/2a = -(32)/2(-16) = -32/-32 = 1 second

then

h(t) = -16(1)^2 + 32(1) = -16 + 32 = 16

After 1 second, the ball will reach a maximum height of 16 feet

8 0
2 years ago
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