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Sedbober [7]
3 years ago
7

Solve the logarithmic equation. When necessary, round answer to the nearest hundredth. logx 36 = 2

Mathematics
1 answer:
Vika [28.1K]3 years ago
3 0

Answer:

x=6

Step-by-step explanation:

We have been given a logarithmic equation \text{log}_x(36)=2. We are asked to solve our given equation.

Using log rule \text{log}_a(b)=\frac{\text{ln}(b)}{\text{ln}(a)}, we will get:

\text{log}_x(36)=\frac{\text{ln}(36)}{\text{ln}(x)}

Substituting back this value, we will get:

\frac{\text{ln}(36)}{\text{ln}(x)}=2

Multiply both sides by \text{ln}(x):

\frac{\text{ln}(36)}{\text{ln}(x)}\times\text{ln}(x)=2\times\text{ln}(x)

\text{ln}(36)=2\times\text{ln}(x)

Switch sides:

2\times\text{ln}(x)=\text{ln}(36)

2\times\text{ln}(x)=\text{ln}(6^2)

Using property \text{log}_a(x^b)=b\cdot \text{log}_a(x), we will get:

2\times\text{ln}(x)=2\cdot \text{ln}(6)

\frac{2\times\text{ln}(x)}{2}=\frac{2\cdot \text{ln}(6)}{2}

\text{ln}(x)=\text{ln}(6)

Since base of both sides are equal, therefore, the value of x is 6.

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The given function is,

y=-5\cos (\frac{\pi}{2}(x-3))+6

The graph can be drawn as,

The period will be distance between two consequetive maximas,

\text{Period}=1-(-3)=4

Thus, period is correct.

The amplitude can be determined as,

\begin{gathered} Amplitude=\frac{\max -\min }{2} \\ =\frac{11-1}{2} \\ =5 \end{gathered}

Thus, amplitue is incorrect.

The range is,

y\in\lbrack1,11\rbrack

Thus, the range is correct.

The midline is,

\begin{gathered} \text{midline}=\frac{\max +\min }{2} \\ =\frac{1+11}{2} \\ =6 \end{gathered}

Thus, the midline is correct.

Thus, option (b) is the solution.

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