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3 years ago

The function g is defined by the following rule. g(x) = 4x + 2 Complete the function table.

Mathematics

1 answer:

Vsevolod [243]3 years ago

4 0

Answer: g(x)= solve for x

G(x)=4x+2

I think 4x+2 is in standard form but if not

Do divid by four

Which is about 0.5

X=0.5

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Given f(x)=4x^3+7x^2-7x-10 factor f(x), given that -1 is a zero

stira [4]

If - 1 is a zero then
$(x + 1)$
is a factor.

Dividing with this factor using the long division approach, we get the quadratic factor to be,

$4 {x}^{2} + 3x - 10$
(see attachment).

We can rewrite the polynomial as
$f(x) = (x + 1)(4 {x}^{2} + 3x - 10)$

We can further factor as

$f(x) = (x + 1)(4 {x}^{2} - 5x + 8x - 10)$
That is

$f(x) = (x + 1)(x + 2)(4x - 5)$

7 0

3 years ago

Find the height <br> 11in 14in<br> h=

jeka57 [31]

Answer:

$h = \sqrt{72}in$

Step-by-step explanation:

We have a right triangle with long side of 11in and smaller sides 14in/2=7in and h.

We know that

$h^2 + (7in)^2 = (11in)^2\\h^2 = 121in^2 - 49in^2 = 72in^2\\h = \sqrt{72}in$

6 0

3 years ago

If a quadratic function has x-intercepts at (-7,0) and 10,0), where would

madam [21]

Answer:

x = 1.5

Step-by-step explanation:

Since the axis of symmetry is between the 2 x intercepts, we can find it by finding the average of the x-coordinates of the 2 points.

(-7 + 10) / 2

3/2

= 1.5

So, the axis of symmetry is at x = 1.5

8 0

3 years ago

A table is in the shape of a regular pentagon with a side length of 3 feet and an

ehidna [41]

Answer:

15.5 ft²

Step-by-step explanation:

The area (A) of a regular polygon is calculated as

A = $\frac{1}{2}$ pa ( p is the perimeter and a the apothem )

Here side of regular pentagon is 3 ft, thus

perimeter = 5 × 3 = 15, so

A = 0.5 × 15 × 2.06 ≈ 15.5 ft ( to the nearest tenth )

8 0

3 years ago

Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0

eduard

If you're using the app, try seeing this answer through your browser: brainly.com/question/2787701

_______________

$\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}$

Square both sides:

$\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}$

$\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}$

Since $\mathsf{sin\,\theta}$ is positive, you can discard the negative sign. So,

$\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}$

Substitute this value back into $\mathsf{(i)}$ to find $\mathsf{cos\,\theta:}$

$\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

7 0

3 years ago