The entire circle has a central angle of 360°.
Because the radius is 6 mi, the area of the circle is
π(6)² = 36π mi².
The sector has a central angle of 60°, therefore it occupies 60/360 = 1/6 of the area of the circle.
The area of the sector is
(1/6)*36π = 6π mi² = 18.85 mi²
Answer: 6π mi² or 18.85 mi².
Answer:
A. The height of the plant after week 3 was about 2.6 inches.
C. The height of the plant after week 9 was about 3.8 inches.
Step-by-step explanation:
The equation given:
Y = 0.2x + 2
x represents the number of weeks
substituting x = 3 into the equation , we will have
y = 0.2(3) + 2
y = 0.6 + 2
y = 2.6
This means that the height of the plant after week 3 was about 2.6 inches.
Also , substituting x = 9 into the equation will give
y = 0.2 (9) + 2
y = 1.8 + 2
y = 3.8
This means that the height of the plant after week 9 was about 3.8 inches.
Answer:
63
Step-by-step explanation:
You have to subtract 180 and 117 which is 63.
Answer: Gary needs to work more than 25hours for the week to earn above $400.
Step-by-step explanation:
For Gary to be paid $50 per week means he worked $50/ $15.50= 3.23 hours for the week.
To make over $400 this week he needs to work for
400/15.50 = 25.81 hours and more for the week to earn above $400
1.) The sum(addition) of 21 and 5 times(multiplication) a number f is(=) 61.
f = unknown number/variable [So 21 plus 5f(5 times f) equals 61]
21 + 5f = 61 [21(one-time) + 5f(number x variable) = 61(total)]
2.) Seventeen more(addition) than seven times(multiplication) a number j is(=) 87.
j = unknown number/variable [So 17 plus 7j(7 times j) equals 87]
17 + 7j = 87
3.) n = number of calls
18 + 0.05n = 50.50
[Company charges $18 plus five cents per call(n), and the total charge was $50.50]
4.) s = the number of students
40 + 30s = 220
[Tutor charges $40 plus $30 per student(s), and the total charge was $220]
