The ratio for the problem above is one to four. A ratio is a relationship between number which describes how many times the second number contains the first number. The problem above gave two metric unit of length which are the centimeter and meter and the ratio between those two is one to a hundred. Therefore, we have a comparison between two amounts which are 75 and 300 and we can conclude a ratio of one to four.
Okay, so the ratio is 3:2 (cylinder to cone)
The equation for finding the volume of a cylinder is V=pi*r^2*h (h stands for height)
We plug in the values: V=3.14*4*4*9
This equals 452.16.
Next, the cone. It’s formula is: V=pi*r^2*h/3
Plugging in the values we get: V=3.14*4*4*18/3 (simplifying to 6)
Solving we get: 301.44.
When we divide 301.44 by 2 we get 150.72
(I originally divided 452.16/301.44 to find the scale factor) Now we multiply 150.72 by 3 to get 452.16, and we already know that 150.72 times 2 equals 301.44. So the ratio is 3:2.
I hope this helps!
Answer:
Lo: - 94o F
Step-by-step explanation:
Hi: 98oF
Difference: 192 degrees lower
Low: ?
Formula
98 - 192 = -94
That seems incredibly cold. I've lived through a day that was - 60oF and that was enough. (about - 51o C)
If you think in Celcius
The formula is
C = 5/9(F - 32)
C = 5/9 (-94 - 32)
C = 5/9 (-126)
C = -60
I think Siberia must be much colder than -60.
Answer:
D
Step-by-step explanation:
Answer:
80 lb of salt
Step-by-step explanation:
Let us assume the water flows into the rank for x minutes.
There is an initial of 60 gallons of water in the tank and water flows in at 3 gal/min. In x minute, the amount of water in the tank = 60 + 3x
Water flows out at 1 gal/min, therefore in x minute the amount of water in the tank = 60 + 3x - x = 60 + 2x
The tank begins to overflow when it is full (has reached 130 gallons). Therefore:
130 = 60 + 2x
2x = 130 - 60
2x = 70
x = 35 minutes.
In 35 minutes the tank would start to overflow.
1 lb salt per gallon flows into the tank at 3 gal/min, in 35 min the amount of salt that entered the tank = 3 gal/min × 35 min × 1 lb/gal = 105 lb
1 lb salt per gallon flows out of the tank at 1 gal/min, in 35 min the amount of salt that flow out of the tank = 1 gal/min × 35 min × 1 lb/gal = 35 lb
Initially there is 10 lb of salt dissloved into 60 gallons of water.
Therefore the amount of salt is in the tank when it is about to overflow = 10 + 105 - 35 = 80 lb of salt.