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2 years ago

How do you find the x-intercepts if given the following polynomial in factored form?

Mathematics

1 answer:

elena-14-01-66 [18.8K]2 years ago

3 0

Answer:

Step-by-step explanation:

You know the intercepts occur at x = 0, so set each part of the factored form equal to zero and solve for x.

The first part, plain X = 0, so X = 0 is a root, an x-intercept

The second part (X-2)^2 = 0, so X = 2 is another root. Since the function is being squared, this root will happen twice. The function crosses this root twice.

The third part (x+4) = 0, so x = -4 is another root.

Finally, (x+1) so x = -1 is another root.

So you have X = 0, X = 2, X = -4, X = -1 as your x-intercepts

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dolphi86 [110]

Answer:

y=-15

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3 years ago

What is a simplified eCarlotta thinks that 3y + 5y3 is the same as 8y4. Which statement shows that it is NOT the same?Xpression

stira [4]

Questions:

(a) What is a simplified expression for (x + y) – (x – y)?

(b) Carlotta thinks that $3y + 5y^3$ is the same as $8y^4$ . Which statement shows that it is NOT the same?

Answer:

$(x + y) - (x - y) =2y$

$3y + 5y^3 \ne 8y^4$

Step-by-step explanation:

Solving (a):

Given

$(x + y) - (x - y)$

Required

Simplify

$(x + y) - (x - y)$

Open brackets

$(x + y) - (x - y) = x + y - x + y$

Collect Like Terms

$(x + y) - (x - y) = x - x+ y + y$

$(x + y) - (x - y) = y + y$

$(x + y) - (x - y) =2y$

Solving (b):

Given

$3y + 5y^3$ and $8y^4$

Required

Which expression shows they are not the same

The expression that shows this is:

$3y + 5y^3 \ne 8y^4$

Take for instance; y=2

Substitute 2 for y in $3y + 5y^3 \ne 8y^4$

$3*2 + 5*2^3 \ne 8*2^4$

Evaluate all exponents

$9 + 5*8 \ne 8*16$

$9 + 40 \ne 128$

$49 \ne 128$

The above expression supports $3y + 5y^3 \ne 8y^4$

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

The vertices of a polygon are P(0,4), Q(5,4), R(5,−3) and S(0,−3). What is

andrezito [222]

Answer:

Perimeter of the polygon p = 24

Step-by-step explanation:

Step(i):-

Given the vertices of a polygon are

P(0,4) ,Q( 5,4) ,R( 5,-3) and S(0,-3)

The distance of PQ

$a = PQ = \sqrt{(4-4)^{2} +(5-0)^{2} } = \sqrt{25} =5$

The distance of QR

$b = Q R= \sqrt{(-3-4)^{2} +(5-5)^{2} } = \sqrt{49} =7$

The distance of RS

$c = RS = \sqrt{(0-5)^{2} +(-3+3)^{2} } = \sqrt{25} =5$

The distance of PS

$d = PS = \sqrt{(0-0)^{2} +(-3-4)^{2} } = \sqrt{49} =7$

Step(ii):-

Perimeter of the polygon

= sum of all sides of polygon

p = a+ b+ c+ d

p = 5+7+5+7

p = 24

Final answer:-

Perimeter of the polygon p = 24

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