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svet-max [94.6K]
2 years ago
8

How do you find the x-intercepts if given the following polynomial in factored form?

Mathematics
1 answer:
elena-14-01-66 [18.8K]2 years ago
3 0

Answer:

Step-by-step explanation:

You know the intercepts occur at x = 0, so set each part of the factored form equal to zero and solve for x.

The first part, plain X = 0, so X = 0 is a root, an x-intercept

The second part (X-2)^2 = 0, so X = 2 is another root. Since the function is being squared, this root will happen twice. The function crosses this root twice.

The third part (x+4) = 0, so x = -4 is another root.

Finally, (x+1) so x = -1 is another root.

So you have X = 0, X = 2, X = -4, X = -1 as your x-intercepts

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dolphi86 [110]

Answer:

y=-15

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7 0
3 years ago
What is a simplified eCarlotta thinks that 3y + 5y3 is the same as 8y4. Which statement shows that it is NOT the same?Xpression
stira [4]

Questions:

(a) What is a simplified expression for (x + y) – (x – y)?

(b) Carlotta thinks that 3y + 5y^3 is the same as 8y^4. Which statement shows that it is NOT the same?

Answer:

(x + y) - (x - y) =2y

3y + 5y^3 \ne 8y^4

Step-by-step explanation:

Solving (a):

Given

(x + y) - (x - y)

Required

Simplify

(x + y) - (x - y)

Open brackets

(x + y) - (x - y) = x + y - x + y

Collect Like Terms

(x + y) - (x - y) = x - x+ y  + y

(x + y) - (x - y) = y  + y

(x + y) - (x - y) =2y

Solving (b):

Given

3y + 5y^3 and 8y^4

Required

Which expression shows they are not the same

The expression that shows this is:

3y + 5y^3 \ne 8y^4

Take for instance; y=2

Substitute 2 for y in 3y + 5y^3 \ne 8y^4

3*2 + 5*2^3 \ne 8*2^4

Evaluate all exponents

9 + 5*8 \ne 8*16

9 + 40 \ne 128

49 \ne 128

The above expression supports 3y + 5y^3 \ne 8y^4

5 0
2 years ago
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Answer:

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Step-by-step explanation:

Alright, there was a lot of addition, and you're just gonna have to trust me, the answer is 320 yards

6 0
2 years ago
The vertices of a polygon are P(0,4), Q(5,4), R(5,−3) and S(0,−3). What is
andrezito [222]

Answer:

 Perimeter of the polygon p = 24

Step-by-step explanation:

Step(i):-

Given the vertices of a polygon are

P(0,4) ,Q( 5,4) ,R( 5,-3) and S(0,-3)

The distance of PQ

 a = PQ = \sqrt{(4-4)^{2} +(5-0)^{2} }  = \sqrt{25} =5

The distance of QR

b = Q R= \sqrt{(-3-4)^{2} +(5-5)^{2} }  = \sqrt{49} =7

The distance of RS

c = RS = \sqrt{(0-5)^{2} +(-3+3)^{2} }  = \sqrt{25} =5

The distance of PS

d = PS = \sqrt{(0-0)^{2} +(-3-4)^{2} }  = \sqrt{49} =7

<u><em>Step(ii):-</em></u>

Perimeter of the polygon

       = sum of all sides of polygon

p = a+ b+ c+ d

p = 5+7+5+7

p = 24

<u><em>Final answer:-</em></u>

 Perimeter of the polygon p = 24

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3 years ago
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