All categories

3 years ago

Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!

Mathematics

1 answer:

IRISSAK [1]3 years ago

8 0

Answer:

30 m

Step-by-step explanation:

Picture the question as a triangle

The length of the string is the hypotenuse, 60 m

The angle from the ground is 30

The right angle C is from the height of the kite to the ground

The missing angle A 60 is located on the top of the kite

now find b, the height

The cosine of an angle is equal to the ratio of the adjacent side to the hypotenuse.

cos(A)=adj/hyp

cos(A)=b/c

b=c*cos(A)

b=60*cos(60)

b=30

You might be interested in

Denny lives in Maryland and pay 6% in sales tax. He just bought $145 in groceries, but $70 worth of those groceries were non tax

SpyIntel [72]

the answer should $201.25

6 0

4 years ago

Read 2 more answers

Can i have some help i need to find the surface area

makkiz [27]

Answer:

644ft^2

Step-by-step explanation:

Area of triangle=1/2bh

Area of square=l*l

so we have;

4 triangles with a base of 14ft and height of 16ft and 1 square with l=14ft

AreaTriangle=1/2(14ft)(16ft)=112ft*4=448ft^2

AreaSquare=14ft*14ft=196ft^2

Area Total=448ft+196ft=644ft^2

7 0

4 years ago

PLEASE ANSWER OFFERING BRAINLEST

jonny [76]

we can establish a ratio since triangle MNQ is equal to Triangle MLP.

your answer is B 9 inches

6 0

3 years ago

3. WHAT IS THE END BEHAVIOR?SHOW WORK.<br><br> - 10x -x+ 2

nekit [7.7K]

Answer:

Step-by-step explanatio

−10x−x+2

=−10x+−x+2

=(−10x+−x)+(2)

=−11x+2

Answer:

=−11x+2

3 0

3 years ago

If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c

dolphi86 [110]

Given:

$(ax+2)(bx+7)=15x^2+cx+14$

And

$a+b=8$

Required:

To find the two possible values of c.

Explanation:

Consider

$\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}$

$\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}$

And also given

$a+b=8---(2)$

Now from (1) and (2), we get

$\begin{gathered} a+\frac{15}{a}=8 \\ \\ a^2+15=8a \\ \\ a^2-8a+15=0 \end{gathered}$ $a=3,5$

Now put a in (1) we get

$\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}$

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

$\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}$

When a=5 and b=3, we have

$\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}$

Final Answer:

The option D is correct.

31 and 41

8 0

1 year ago