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Sever21 [200]
3 years ago
13

Jackson is building a bookshelf and has a piece of wood that is 5/8 foot long. He needs to cut pieces that are 1/16 foot long. H

ow many pieces can Jackson cut?
Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
8 0

Answer: 10 pieces

Step-by-step explanation:

So, 5/8 divided by 1/16 is 10.

Therefore Jackson can cut 10 pieces.

strojnjashka [21]3 years ago
3 0

Answer:

<h2>6 is the answer</h2><h2 />

A fraction consists of two parts the top number and the bottom one.

Think of the top number as the count and the bottom as the size indicator. So you have:

countsize indicator −−−−−−−−−−→proper names numeratordenominator

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Consider the action example of dividing 3 into 6.

We can do this division directly because their size indicators are the same. That is, we have: 61÷31. People do not normally write it this way but it is correct.

To directly divide the counts the size indicator must be the same

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

So we need to see how many of 18 will fit into 34

We can not do this directly in one operation as the size indicators are not the same.

Lets make the size indicators (denominators) the same

Multiply by 1 and you do not change the value but

1 comes in many forms.

[34×1]÷18 → [34×22]÷18

[3×24×2]÷18 → 68÷18

Now that the size indicators (denominators) are the same we can just divide the counts (numerators)

countsize indicator→[68÷18]=6÷1=6

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

I could explain more showing the connection between this and the shortcut method but what I have shown you will do for now.

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5 0
3 years ago
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6 0
3 years ago
Locate the mean of 2046,971,3113,and 1850.
Debora [2.8K]
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4 years ago
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mash [69]

Answer:

D

Step-by-step explanation:

Lets go case by case.

Given the roots, a factor will be part of the equation if for some of the roots the factor becomes null, i.e., equal to 0.

Is there any root that makes (x+3)=0? No, as it only becomes 0 for x = - 3 and -3 is not a root. So A NO!

Is there a root that makes (x-1)=0? No, as it only becomes 0 for x=1 and 1 is not a root. So B NO!

(x-4)=0 only for x=4, and as 4 is not a root, C NO!

The last, (x-3)=0 if x=3. As 3 is one of the roots, (x-3) is a factor of our equation!

D is the only correct option!

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