Question

Find the linear equation that is the straight line through (1, 2) and (8, 30).​

Answer 1

Answer:

y = 4x - 2

Step-by-step explanation:

→ First find the gradient

$\frac{x2-x1}{y2-y1} =\frac{30-2}{8-1} = 4$

→ Put into y = mx + c format

y = 4x + c

→ Substitute ( 1 , 2 ) into y = 4x + c

2 = 4 + c so c = -2

→ Rewrite into equation format

y = 4x - 2

Answer 2

Slope
= 30-2/8-1

= 28/7

= 4


Equation:
y - 2/x - 1 = 4

y - 2 = 4(x-1)

y - 2 = 4x - 4

y = 4x - 4 + 2

y = 4x - 2