Is this the right answer?,please help before I turn it in

3. On a morning walk, Betty, Christine and Ann step off together. Their steps measure 50, 75

BaLLatris [955]

Answer:

they can all walk 90

Step-by-step explanation:

8 0

2 years ago

HELP ASAP!!!!!!!!!!!!!

OLEGan [10]

Answer:

∠ABC=90°

Step-by-step explanation:

if ∠DAB =110 then ∠BAC =180-110 =70° because straighht lines make 180°∠s

use the fact that the sum of angles in a Δ is 180°

∠ABC= 180-20-70= 90

7 0

2 years ago

Convert the decimal expansion 0.1777 into a rational number

Helen [10]

Answer:

The rational form of the given number 0.1777 = $\frac{1777}{10,000}$

Step-by-step explanation:

The rational number is expressed as a number on the form of $(\frac{p}{q} ) , q \neq 0$

Now,here the given number in decimal form = 0.1777

To remove the decimal, firstly count the number of digits AFTER DECIMAL.

Here, number of digits after decimal = 4

SO, the decimal can be removed and replaced by 1 , by dividing with 1,0000.

$\implies 0.1777 = \frac{01,777} {10,000} = \frac{1777}{10,000}$

Hence, the rational form of the given number 0.1777 = $\frac{1777}{10,000}$

5 0

2 years ago

A small rocket is fired from a launch pad 10 m above the ground with an initial velocity left angle 250 comma 450 comma 500 righ

jonny [76]

Let $\vec r(t),\vec v(t),\vec a(t)$ denote the rocket's position, velocity, and acceleration vectors at time $t$ .

We're given its initial position

$\vec r(0)=\langle0,0,10\rangle\,\mathrm m$

and velocity

$\vec v(0)=\langle250,450,500\rangle\dfrac{\rm m}{\rm s}$

Immediately after launch, the rocket is subject to gravity, so its acceleration is

$\vec a(t)=\langle0,2.5,-g\rangle\dfrac{\rm m}{\mathrm s^2}$

where $g=9.8\frac{\rm m}{\mathrm s^2}$ .

a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,

$\vec v(t)=\left(\vec v(0)+\displaystyle\int_0^t\vec a(u)\,\mathrm du\right)\dfrac{\rm m}{\rm s}$

$\vec v(t)=\left(\langle250,450,500\rangle+\langle0,2.5u,-gu\rangle\bigg|_0^t\right)\dfrac{\rm m}{\rm s}$

(the integral of 0 is a constant, but it ultimately doesn't matter in this case)

$\boxed{\vec v(t)=\langle250,450+2.5t,500-gt\rangle\dfrac{\rm m}{\rm s}}$

and

$\vec r(t)=\left(\vec r(0)+\displaystyle\int_0^t\vec v(u)\,\mathrm du\right)\,\rm m$

$\vec r(t)=\left(\langle0,0,10\rangle+\left\langle250u,450u+1.25u^2,500u-\dfrac g2u^2\right\rangle\bigg|_0^t\right)\,\rm m$

$\boxed{\vec r(t)=\left\langle250t,450t+1.25t^2,10+500t-\dfrac g2t^2\right\rangle\,\rm m}$

b. The rocket stays in the air for as long as it takes until $z=0$ , where $z$ is the $z$ -component of the position vector.

$10+500t-\dfrac g2t^2=0\implies t\approx102\,\rm s$

The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):

$\boxed{\|\vec r(102\,\mathrm s)\|\approx64,233\,\rm m}$

c. The rocket reaches its maximum height when its vertical velocity (the $z$ -component) is 0, at which point we have

$-\left(500\dfrac{\rm m}{\rm s}\right)^2=-2g(z_{\rm max}-10\,\mathrm m)$

$\implies\boxed{z_{\rm max}=125,010\,\rm m}$

7 0

2 years ago

NEED HELP PLEASE BEGGING PLEASE!!!!

Sliva [168]

Answer:

-54

Step-by-step explanation:

$8(-9) - 6(-3)\\$

Multiply 8 by -9 and 6 by -3

$-72 - (-18)$

Subtract $Value = -54$

Hope this helps

plz mark brainliest

6 0

2 years ago