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PSYCHO15rus [73]
3 years ago
7

Is this the right answer?,please help before I turn it in

Mathematics
1 answer:
astraxan [27]3 years ago
5 0
Yes it’s the right answer, I just did it myself and I got -4
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What's substitution for y=4x-1, 2x+y=5
Dennis_Churaev [7]

Step-by-step explanation:

y = 4x-1

2x+y = 5

2x+(4x-1) = 5

6x - 1 = 5

6x = 6

x = 1

4 0
3 years ago
Read 2 more answers
Choose a number between and that is a multiple 45 of and 95 . Write all the numbers that she could choose. If there is more than
AnnZ [28]

Answer with explanation:

To find the common multiple of 45 and 95,we will find HCF of 45 and 95.

45=3 × 3× 5

95=5 × 19

⇒H CF(45,95)

=3 × 3×5×19

=855

→Common multiple of 45 and 95 =855

→There are infinite number of multiple of 855 which are 855, 1710, 2565,.....

You have not written between which two numbers.So, you should write multiple of 855 such that it is smaller than the greater number.

7 0
3 years ago
Lynn plotted point G, 3 units to the left and 2 units above point F . Where did Lynn plot point G ?
bekas [8.4K]

Answer:

(2, 6)

Step-by-step explanation:

Point G has a coordinate of x = 5, and y = 4, that is (5, 4).

If Lynn plots point G, such that:

G is 3 units to the left of point F, the x-coordinate of point G = 5 - 3 = 2

G is 2 units above point F, the y-coordinate of point G = 4 + 2 = 6.

Therefore, Lynn plotted point G at x = 2, and y = 6. Which is (2, 6)

3 0
3 years ago
Solve for x. Show your work.
puteri [66]
So, these are actually pretty simple once you learn the equality used to solve for "x" and when to implement this method. You can use this equality to solve for a segment "x" anytime that two secant lines cutting through a circle come from the same point outside the circle. 

Secant: by geometric definition is just a straight line that cuts a curve into multiple pieces.

I did one of them for you hopefully you can use my work for "a" to help you solve for "b".  For a. I got x=7.

6 0
4 years ago
Koby can work about 22 math problems in 30 minutes. At this rate, how many math problems can Koby work in 3 hours
-BARSIC- [3]
So 22 problems/ 30 minutes = ? problems/ 180 minutes
so you basically just convert them
and you will times 30 by 6 to get 180, so you times 22 by 6 
and you will get 132 problems

so Koby can do 132 problems
4 0
3 years ago
Read 2 more answers
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