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3 years ago

Help!! I'll name you the brainliest!!

Mathematics

1 answer:

Lunna [17]3 years ago

4 0

Just get a brain

Jksjsisisisjsjjsjdjdjdjd

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(X^2+3)^2 - (x^2-1)^2

Julli [10]

Answer:

8(X^2+1)

Step-by-step explanation:

(X²+3)²-(X²-1)

(X²+3)(X²+3)-(X²-1)(X²-1)

X⁴+3X²+3X²+9-(X⁴-X²-X²+1)

X⁴+6X²+9-(X⁴-2X²+1)

X⁴+6X²+9-X⁴+2X²-1

8X²+8

3 0

3 years ago

The average ticket price for a concert at the opera house was $50. The average attendance was 4000. When the ticket price was ra

kotegsom [21]

Answer

given,

opera house ticket = $50

attendance = 4000 persons

now,

opera house ticket = $52

attendance = 3800 person

assuming these are the points on the demand curve

(x, p) = (4000,50) and (x,p) = (3800,52)

using point slope formula

$p-50 = \dfrac{50-52}{4000-3800}(x - 4000)$

$p-50 = \dfrac{-2}{200}(x - 4000)$

$p-50 = \dfrac{-x}{100}+ 40$

$p = \dfrac{-x}{100}+ 90$

R(x) = x . p

$R(x) = x (\dfrac{-x}{100}+ 90)$

$R(x) = \dfrac{-x^2}{100}+ 90x)$

$\dfrac{d}{dx}(R(x)) = \dfrac{d}{dx}(\dfrac{-x^2}{100}+ 90x))$

$\dfrac{d}{dx}(R(x)) = (\dfrac{-2x}{100})+90)$

at $\dfrac{d}{dx}(R(x)) = 0$

$\dfrac{-2x}{100}= -90$

x = 4500

$\dfrac{d^2}{d^2x}(R(x)) = -ve$

hence at x =4500 the revenue is maximum

for maximum revenue ticket price will be

$p = \dfrac{-4500}{100}+ 90$

p = $45

6 0

4 years ago

What is the area of a rectangle with side lenghts 3x+2 and x-4

melamori03 [73]

For a rectangle, A = LW.

A = (3x + 2)(x - 4)

A = 3x^2 - 12x + 2x - 8

A = 3x^2 -10x - 8

6 0

4 years ago

A square has a perimeter of 12x + 52 units which expression represents the side length of the square units

Anarel [89]

The perimeter of a square: P = 4s.

The equation:

4s = 12x + 52 |:4

s = 3x + 13

7 0

3 years ago

Please help quickly!!!

stiks02 [169]

Answer:

Option D is correct.

$(2x^5y^2)^3= 8x^{15}y^6$

Step-by-step explanation:

Power of product property:

$(x^m)^n = x^{mn}$

$(ax)^m = a^m \cdot x^m$

Let the equation: $(2x^5y^2)^3$

Using power of products Property on given equation:

$(2x^5y^2)^3$ = $2^3 \cdot (x^5)^3 \cdot (y^2)^3 = 8 \cdot x^{15} \cdot y^6 = 8x^{15}y^6$

Therefore, the only option D of an equation which shows the correct use of power of Products property is, $(2x^5y^2)^3= 8x^{15}y^6$

4 0

3 years ago

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