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2 years ago

Can somebody help me please.

Mathematics

1 answer:

olga55 [171]2 years ago

5 0

Let x and x+1 be the two consecutive integers.

Then their sum is x + (x+1) = 2x + 1.

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The function f(x) is shown on the graph.

Sever21 [200]

The value of f(0) is 12.

<h3>What is graph?</h3>

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

By considering the graph we have to find f(0) which means we have to find that point where x- coordinate is zero.

Also, which shows that 12 the function f(x)

So, taking the point is (0,12) we can get f(0)= 12.

Learn more about this concept here:

brainly.com/question/16608196

#SPJ1

7 0

1 year ago

Last week Sarah lost' 6.25 pounds but this week she gained 4.6 pounds. What was her overall weight change?

marissa [1.9K]

Answer:

10.85

Step-by-step explanation:

hope its right :)

6 0

2 years ago

HELP!!! PLZZ THIS IS SO FRICKIN HARD!

krek1111 [17]

Answer:

14.3%

Step-by-step explanation:

1/7=0.142857142857

round that to the nearest tenth and that is 0.143

make it a percentage and it is 14.3%

8 0

2 years ago

Given m||n, find the value of x.<br> (9x-5)(6x+20)

xxTIMURxx [149]

Answer:

5/9 & -10/3

Step-by-step explanation:

Set each to 0 and solve:

9x-5 = 0

9x=5

x=5/9

6x+20=0

6x=-20

x=-20/6

x= -10/3 or -3 1/3

7 0

2 years ago

Find \tan\left(\frac{17\pi}{12}\right)tan( 12 17π )tangent, left parenthesis, start fraction, 17, pi, divided by, 12, end frac

uranmaximum [27]

One way to do this is to notice

$\dfrac{17\pi}{12}=\dfrac\pi6+\dfrac{5\pi}4$

Then

$\tan\dfrac{17\pi}{12}=\tan\left(\dfrac\pi6+\dfrac{5\pi}4\right)=\dfrac{\tan\frac\pi6+\tan\frac{5\pi}4}{1-\tan\frac\pi6\tan\frac{5\pi}4}$

We have

$\tan\dfrac\pi6=\dfrac{\sin\frac\pi6}{\cos\frac\pi6}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

and since $\tan x$ has a period of $\pi$ ,

$\tan\dfrac{5\pi}4=\tan\left(\pi+\dfrac\pi4\right)=\tan\dfrac\pi4=1$

and so

$\tan\dfrac{17\pi}{12}=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3$

7 0

3 years ago

Can somebody help me please.​

Can somebody help me please.