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Alina [70]
3 years ago
9

HELP ASAP!!!!! Find the lateral surface area and the total surface area of each figure. round to the nearest tenth if needed. SH

OW ALL WORK. (Will give brainliest for correct answer and explanation on what to do)+

Mathematics
1 answer:
zysi [14]3 years ago
4 0

Answer:

(1-2) LS = 288cm² TS = 378cm²

(3-4) LS = 1419.2 TS = 1673.5

(5) LS = 543 TS = 606

Step-by-step explanation:

(1-2)

7 1/2 = 7.5

7.5 x 15 = 112.5

9 x 12  ➗ 2 = 54

54 x 2 = 108

9 x 7.5 = 67 .5

(3-4)

3.14 x 81 = 254.3

(5)

9 x 15 = 135 x 2 = 270

15 x 7 = 105 x 2 = 210

9 x 7 = 63

(add)

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Step-by-step explanation:

-5a-6a-3+8

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A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What
Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}

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P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174

b)  What is the probability that at least one is essay?

P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232

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3 years ago
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