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natita [175]
3 years ago
15

A ship sonar detects an echo 1.6s after it sends the pluse.The speed of sound in water in 1500mls work out how deep the water is

Biology
1 answer:
yaroslaw [1]3 years ago
6 0

Answer:

1200m

Explanation:

Let the depth of sea be x.

Given that the sound has to travel to the bottom of the sea and get reflected back to the ship itself, thus total distance traveled by the sound is 2x.

Time taken to hear an echo t=1.6 s

Therefore, 2x = vt

Hence, we have 2x =1500m/s × 1.6s

=> 2x = 2400

⟹ x = 2400 ÷ 2

= 1200m

Hence, the final answer is 1200m

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Zarrin [17]

Answer:

Statement 1: Homologous chromosomes line up at the equator in pairs.

Name of Phase: Metaphase 1

Sequence: 3

Statement 2: The cell replicates its chromosomes

Name of Phase: S-Phase, Interphase

Sequence: 1

Statement 3: Homologous chromosomes separate and move to opposite poles of the cell

Name of Phase: Anaphase 1

Sequence: 4

Statement 4: Spindle forms, DNA coils up in homologous chromosomes come together in a tetrad; crossing over may occur.

Name of Phase: Prophase 1

Sequence: 2

Statement 5: Events occur in reverse order of prophase 1

Name of Phase: Telophase 1

Sequence: 5

Explanation:

Following is a summary of the events of meiosis:

1. Interphase:

Prepares the cell for division. Duplication of DNA, duplication of centrioles occurs and the cell grows in size. At this stage the cell is diploid (2n).

2. Prophase 1:

First stage of Meiosis 1.The centrioles move to the poles of the cell, the nuclear membrane disintegrates, homologous chromosomes pair up (in the form of tetrad), form a chiasmata and then exchange segments of chromosomes with each other. This process is called crossing over.

3. Metaphase 1:

Involves the arrangement of the crossed over, homologous chromosomes on the metaphase plate which is sort of like a web of spindle fibers that originates from the centrioles.

4. Anaphase 1:

The tetrads arranged on the metaphase plate are pulled apart by the spindle fibers. This is the result of tension that build up in the spindle fibers as they grow towards opposite poles.

5. Telophase 1:

The last stage of meiosis 1. Involves the arrival of the chromosomes at the poles, the nuclear membrane starts to form and the chromosomes start decondensing. Telophase 1 yields 2 daughter cells with half the number of chromosomes as that in the parent cell.

Meiosis 2:

Meiosis 2 is exactly similar to mitosis. The only difference is that the haploid cells entering meiosis 2 do not duplicate their DNA. Meiosis 2 just involves the separation of the sister chromatids of homologous chromosomes.

  • As mentioned above, interphase does not occur before meiosis 2.
  • Prophase 2 involves the disintegration of nuclear envelope, centrosomes start moving to the poles.
  • Metaphase 2 arranges the chromosomes on metaphase plate.
  • Anaphase 2 separates the sister chromatids from the chromosomes.
  • Telophase 2 develops the nuclear envelope and separates the nuclei of the daughter cells into 2. Nuclear division id followed by cytokinesis (division of cytoplasm). Telophase 2 result sin 4 haploid daughter cells with one chromatid from each chromosome.
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3 years ago
Laurita and Trey notice that the two hermit crabs in their class prefer peanut butter over the crab food from the pet store. The
viktelen [127]
They only tested two to have a solid hypothesis you need a larger group.
8 0
3 years ago
Read 2 more answers
Why is the asteroid belt between Mars and Jupiter?
lapo4ka [179]

Answer:

Main Asteroid Belt

Explanation:

It is known as The main astroid Belt

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8 0
3 years ago
Describe the relationship between evolution, genetic mutation, and the environment. ​
Nadusha1986 [10]

Answer:

The meaningful differences between organisms in a population are genetic. Variations in the genome of members of a population arise through mutation. Occasionally, a mutation occurs in an individual that is beneficial, that helps that organism be better able to survive and repoduce in its current environment.

6 0
3 years ago
In a certain plant, tall stems (t) are dominant to short stems (t). a farmer crosses a short-stemmed plant with a heterozygous l
melisa1 [442]

The answers would be:

Genotype                Phenotype

     Tt                      Tall stemmed

     tt                       Short stemmed

Genotypic ratio : 2:2 or 1:1

Phenotypic ratio: 2:2  or 1:1  

<u />

<u>You can read on to see how this was done:</u>

Tall stems (T) are dominant to short stems (t).

First figure out the genotypes of the parents. We have a short-stemmed plant and a heterozygous long-stemmed plant cross.

For short stem to occur, you need 2 pairs of short alleles. So the first parent would have a genotype of tt.

Heterozygous long-stemmed means that the parent has one of each allele. So the genotype of the second parent would be, Tt.

Now we can make our Punnett Square.

tt x Tt

<u>       t        t  </u>

<u>T |  Tt  |   Tt</u>

<u>t  |   tt  |   tt</u>

Let's list down the genotypes and phenotypic results.

Genotype        no.         Phenotype

     Tt                 2           Tall stemmed

     tt                  2           Short stemmed

So from that we can answer the other questions:

Genotypic ratio : 2:2 or 1:1

Phenotypic ratio: 2:2  or 1:1  

8 0
4 years ago
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