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Debora [2.8K]
3 years ago
12

45 x 60 / 45 = ______ pleasee help

Mathematics
1 answer:
AleksandrR [38]3 years ago
8 0

Answer:

60

Step-by-step explanation:

45 x 60/45 = 2700/45

2700/45 = 60

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Customers arrive at a bank drive-up window every 6 minutes based on a Poisson distribution. Once they arrive at the teller, serv
Jet001 [13]

Answer:

(a) 0.01029 (b) 4.167 customers (c) 0.4167 hours or 25 minutes (d) 0.5 hours or 30 minutes

Step-by-step explanation:

With an arrival time of 6 minutes, λ=10 clients/hour.

With a service time of 5 minutes per transaction, μ=12 transactions/hour.

(a) The probability of 3 or fewer customers arriving in one hour is

P(C<=3)=P(1)+P(2)+P(3)

P(X)=\lambda^{X}*e^{-\lambda}  /X!

P(1)=10^{1}*e^{-10}  /1!=0.00045\\P(3)=10^{3}*e^{-10}  /3!=0,00227\\P(2)=10^{2}*e^{-10}  /2!=0,00757\\P(x\leq3)=0.00045+0.00227+0.00757 = 0.01029

(b) The average number of customers waiting at any point in time (Lq) can be calculated as

L_{q}=p*L=\frac{\lambda}{\mu}*\frac{\lambda}{\mu-\lambda}\\L_{q}=\frac{10}{12}*\frac{10}{12-10}\\\\L_{q}=100/24=4.167

(c) The average time waiting in the system (Wq) can be calculated as

W_{q}=p*W=\frac{\lambda}{\mu}*\frac{1}{\mu-\lambda}\\W_{q}=(10/12)*(1/(12-10))\\W_{q}=(10/24)=0.4167

(d) The average time in the system (W), waiting and service, can be calculated as

W=\frac{1}{\mu-\lambda}\\W=\frac{1}{12-10}=0.5

6 0
3 years ago
EASY QUICK POINTS
Alex

the answer is rhombus...

4 0
3 years ago
Read 2 more answers
25 points, please help!!!!!!!!!
Olenka [21]
D, “it is one-half the area of a rectangle of length 2 units and width 4 units.”
HOPE THIS HELPS!!!
5 0
3 years ago
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three consecutive odd integers such that four times the middle integer is two more than the sum of the first and third
Rainbow [258]
Bearing in mind that, if you multiply, any integer whatsoever by 2, you end up with a even integer, 17*2, or 19*2, 88*2 you name it, you get an even number

now, you can get an odd integer by simply going from an even integer, back or forth, so if you have an even number of say  24, 24  - 1, 23, 24+1, 25, 23 and 25 are the odd ones next to 24

so.. let's pick some number, let's say hmm "a", we know 2*a is even, so 2a, thus, 2a +1 or 2a -1 is an odd one.... let's use hmm 2a + 1 as our first odd integer

to jump from an odd integer to another, you simply add 2, 3+2, 5, 5+2, 7 and so on

so... our first one is 2a + 1, so the next consecutive one, will then be (2a+1)+2

and next consecutive after that is (2a+1+2)+2

so our three consecutive odd integers are then

2a + 1
2a + 3
2a + 5


now, 4 times the middle is 4(2a+3)
the sum of the first and last is  (2a+1) + (2a+5)
now, two more than that is just  (2a+1) + (2a+5) + 2

thus

4(2a + 3) = (2a + 1) + (2a + 5) + 2

solve for "a"
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4 years ago
Which of the following statements is true?
Luden [163]

Answer:

i think its b

Step-by-step explanation:

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3 years ago
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