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Komok [63]
3 years ago
13

Answers for the 2 boxes please :)​

Mathematics
2 answers:
scoray [572]3 years ago
7 0

Answer:

(8, - 5 )

Step-by-step explanation:

Given the 2 equations

3x + 4y = 4 → (1)

- x - 3y = 7 → (2)

Multiplying (2) by 3 and adding to (1) will eliminate the x- term.

- 3x - 9y = 21 → (3)

Add (1) and (3) term by term to eliminate x, that is

0 - 5y = 25

- 5y = 25 ( divide both sides by - 5 )

y = - 5

Substitute y = - 5 into either of the 2 equations and solve for x

Substituting into (1)

3x + 4(- 5) = 4

3x - 20 = 4 ( add 20 to both sides )

3x = 24 ( divide both sides by 3 )

x = 8

solution is (8, - 5 )

creativ13 [48]3 years ago
3 0

sorry mine was a mistake

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(−4 + 5) − (6 + 7) = x x 0
weeeeeb [17]

1

Add the numbers

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−

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+

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)

−

(

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(

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+

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2

Add the numbers

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−

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+

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1-({\color{#c92786}{6}}+{\color{#c92786}{7}})=xx^{0}

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1-({\color{#c92786}{13}})=xx^{0}

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3

Multiply the numbers

1

−

1

⋅

1

3

=

0

1{\color{#c92786}{-1}} \cdot {\color{#c92786}{13}}=xx^{0}

1−1⋅13=xx0

1

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1

3

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0

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4

Subtract the numbers

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1

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0

{\color{#c92786}{1-13}}=xx^{0}

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2

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Combine exponents

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Solution

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