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3 years ago

How many times can 10 go into 111?

Mathematics

2 answers:

ElenaW [278]3 years ago

4 0

Answer:

11 times

Step-by-step explanation:

hope this helps

Flauer [41]3 years ago

4 0

Answer:

11.

Step-by-step explanation:

10 x 10 = 100

10 x 11 = 110

10 x 12 = 120 which is too much so its the one above.

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Place a check mark in the box next to each expression that is equivalent to 4^3

damaskus [11]

B, d, e, f

they all equal 64

7 0

3 years ago

use the elimination method to solve the system of equations. choose the correct ordered pair x-y=2 2x+3y=14

son4ous [18]

Answer:

x = 4

y = 2

Step-by-step explanation:

x - y = 2

x = 2 + y

2x + 3y = 14

2(2 + y) + 3y = 14

4 + 2y + 3y = 14

4 + 5y = 14

5y = 10

y = 2

x - y = 2

x - 2 = 2

x = 4

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3 years ago

A cell phone company charges $20 for registration and $0.5 for every minute call, write an equation to model the cost C(x) for u

stealth61 [152]

Answer:

C(x) = 20 + .5m

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is 1/5 times 24 as estimate

Furkat [3]

the estimates or correct answer is 24/5 =4 4/5

4 0

4 years ago

Read 2 more answers

Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu

olga_2 [115]

Answer:

The probability that the selected joint was judged to be defective by neither of the two inspectors is $P(A' n B' ) = 0.8855$

The probability that the selected joint was judged to be defective by inspector B but not by inspector A is $P(A' n B) =0.0403$

Step-by-step explanation:

From the question we are told that

The sample size is $n_s = 10000$

The number of outcome for inspector A is $n__{A}} = 742$

The number of outcome for inspector B is $n__{B}} = 745$

The number of joints judged defective by both inspector is $n(A u B) = 1145$

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

$P(A' n B' ) = 1 - P(A u B)$

Now

$P(A\ u \ B) = \frac{n(Au B)}{n_s }$

substituting values

$P(A\ u \ B) = \frac{1145}{ 10 000 }$

$P(A' n B' ) = 1 - \frac{1145}{10 000}$

$P(A' n B' ) = 0.8855$

the probability that the selected joint was judged to be defective by inspector B but not by inspector A is mathematically represented as

$P(A' n B) = P(A \ u \ B) -P(A)$

Now

$P(A) = \frac{n__{A}}{n_s}$

substituting values

$P(A) = \frac{742}{10 000}$

$P(A' n B) = \frac{1145}{10 000} - \frac{742}{10 000}$

$P(A' n B) =0.0403$

7 0

4 years ago