The answer is 9/10 because I did the test and that was the answer
(7y² + 6xy) - (-2xy + 3)
⇒ (-1 * -2xy) + (-1 * 3) = 2xy - 3
7y² + 6xy + 2xy - 3
7y² + 8xy - 3 Choice B.
Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
(6x -2) 2 (0.5) 4
(6x -2) 4
24x -8
Solution
24x -8