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3 years ago

7

Need help!!!!!! this is for a grade

1 answer:

netineya [11]3 years ago

8 0

C it is C
I think hope this helps

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Help me please help me ASAP please please

Arturiano [62]

Answer:

put 0 first

Step-by-step explanation:

4 0

3 years ago

In the coordinate plane, the point A, 4− 2 is translated to the point A′, 1− 5. Under the same translation, the points B, 7− 4 a

Inga [223]

Answer:

The coordinates of B' and C' are $B'(x,y) = (4, -7)$ and $C'(x,y) = (-1, -8)$ , respectively.

Step-by-step explanation:

From the Linear Algebra, we define the translation of a given point as:

$O'(x,y) = O(x,y) + T(x,y)$ (1)

Where:

$O(x,y)$ - Original point, dimensionless.

$T(x,y)$ - Translation vector, dimensionless.

$O'(x,y)$ - Translated point, dimensionless.

If we know that $A'(x,y) = (1, -5)$ and $A(x,y) = (4,-2)$ , then the translation vector is:

$T(x,y) = A'(x,y)-A(x,y)$ (2)

$T(x,y) = (1,-5)-(4,-2)$

$T(x,y) = (-3,-3)$

If we know that $B(x,y) = (7,-4)$ , $C(x,y) = (2,-5)$ and $T(x,y) = (-3,-3)$ , then the translated points are, respectively:

$B'(x,y) = B(x,y)+T(x,y)$ (3)

$B'(x,y) = (7,-4) +(-3,-3)$

$B'(x,y) = (4, -7)$

$C'(x,y) = C(x,y) +T(x,y)$

$C'(x,y) = (2,-5) + (-3,-3)$

$C'(x,y) = (-1, -8)$

The coordinates of B' and C' are $B'(x,y) = (4, -7)$ and $C'(x,y) = (-1, -8)$ , respectively.

5 0

3 years ago

Quick algebra 1 question for 10 points!

zaharov [31]

<u>Answer:</u>

○ $x = -7$

<u>Step-by-step explanation:</u>

Given the equation:

$10(x + 10) - 4 = 11 - 5(2x + 11)$ ,

to solve for $x$ , we have to rearrange the equation to make $x$ its subject.

$10(x + 10) - 4 = 11 - 5(2x + 11)$

⇒ $10x + 100 - 4 = 11 - 10x -55$ [expand brackets]

⇒ $10x + 96 = -44 - 10x$

⇒ $10x + 10x + 96 = -44$ [add $10x$ to both sides]

⇒ $20x + 96 = -44$

⇒ $20x = -44 - 96$ [subtract 96 from both sides]

⇒ $20x = -140$

⇒ $x = \frac{-140}{20}$ [divide both sides by 20]

⇒ $x = \bf-7$

6 0

2 years ago

Read 2 more answers

What is a solution to the equation 1/8=2/5•x

sleet_krkn [62]

The answer is: x=5/16

3 0

3 years ago

Read 2 more answers

There were 442 students at Deerlake Middle School who voted on a theme for the spring carnival. Those who voted represent 76% of

never [62]

Answer:

Option C is correct.

Step-by-step explanation:

Number of students of Deerlake middle school that voted = 442

Percentage of student that voted = 76%

Let x be the total number of student.

According to the Question,

$\frac{76}{100}\times x=442$

$x=442\times\frac{100}{76}$

$x=582$

Therefore, Option C is correct.

7 0

4 years ago