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2 years ago

Proof that 1^√2 = 1 is true

Mathematics

2 answers:

Reika [66]2 years ago

8 0

Answer:

1^sqrt(2) = 1 is always true

Step-by-step explanation:

mrs_skeptik [129]2 years ago

3 0

Step-by-step explanation:

it is always 1 because the teacher said.....lol

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How do you write ten fifteens in the simplest form for fraction

kirza4 [7]

10/15 divided by 5 = 5/10

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2 years ago

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In triangle ABC angle BAD is 46° find BCA and AB=AD=AC

Shalnov [3]

Look at the picture.

$m\angle a=\dfrac{180^o-46^o}{2}=67^o\\\\m\angle b=180^o-67^o=113^o\\\\m\angle x=\dfrac{180^o-113^o}{2}=33.5^o\\\\Answer:\ [1]\ 33.5^o$

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3 years ago

Part A: Create a third-degree polynomial in standard form. How do you know it is in standard form? (5 points)

Svetlanka [38]

Answer:

(See explanation for further details)

Step-by-step explanation:

a) Let consider the polynomial $p(x) = 5\cdot x^{3} +2\cdot x^{2} - 6 \cdot x +17$ . The polynomial is in standards when has the form $p(x) = \Sigma \limit_{i=0}^{n} \,a_{i}\cdot x^{i}$ , where $n$ is the order of the polynomial. The example has the following information:

$n = 3$ , $a_{0} = 17$ , $a_{1} = -6$ , $a_{2} = 2$ , $a_{3} = 5$ .

b) The closure property means that polynomials must be closed with respect to addition and multiplication, which is demonstrated hereafter:

Closure with respect to addition:

Let consider polynomials $p_{1}$ and $p_{2}$ such that:

$p_{1} = \Sigma \limits_{i=0}^{m} \,a_{i}\cdot x^{i}$ and $p_{2} = \Sigma \limits_{i=0}^{n}\,b_{i}\cdot x^{i}$ , where $m \geq n$

$p_{1}+p_{2} = \Sigma \limits_{i=0}^{n}\,(a_{i}+b_{i})\cdot x^{i} + \Sigma_{i=n+1}^{m}\,a_{i} \cdot x^{i}$

Hence, polynomials are closed with respect to addition.

Closure with respect to multiplication:

Let be $p_{1}$ a polynomial such that:

$p_{1} = \Sigma \limits_{i=0}^{m} \,a_{i}\cdot x^{i}$

And $\alpha$ an scalar. If the polynomial is multiplied by the scalar number, then:

$\alpha \cdot p_{1} = \alpha \cdot \Sigma \limits_{i = 0}^{m}\,a_{i}\cdot x^{i}$

Lastly, the following expression is constructed by distributive property:

$\alpha \cdot p_{1} = \Sigma \limits_{i=0}^{m}\,(\alpha\cdot a_{i})\cdot x^{i}$

Hence, polynomials are closed with respect to multiplication.

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2 years ago

What is x2-12x+36 factored

svetoff [14.1K]

How to get answer by Mimiwhatsup:

$x^2-12x+36\\Break\:the\:expression\:into\:groups\\=\left(x^2-6x\right)+\left(-6x+36\right)\\\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2-6x\mathrm{:\quad }x\left(x-6\right)\\\mathrm{Factor\:out\:}-6\mathrm{\:from\:}-6x+36\mathrm{:\quad }-6\left(x-6\right)\\=x\left(x-6\right)-6\left(x-6\right)\\\mathrm{Factor\:out\:common\:term\:}\left(x-6\right)\\=\left(x-6\right)\left(x-6\right)\\Refine\\Answer: \left(x-6\right)^2$

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3 years ago

18. A rectangular tables has a

Sauron [17]

Area = 7x + 3
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1 year ago

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