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3 years ago

Proof that 1^√2 = 1 is true

Mathematics

2 answers:

Reika [66]3 years ago

8 0

Answer:

1^sqrt(2) = 1 is always true

Step-by-step explanation:

mrs_skeptik [129]3 years ago

3 0

Step-by-step explanation:

it is always 1 because the teacher said.....lol

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The scale of a map is given as 1 : 20000000. Two cities are 6 cm apart on the map. Find the actual distance between them.

larisa [96]

Answer:

The actual distance between the cities is 1,200 Km

Step-by-step explanation:

Scaling

Objects can be represented in a reduced or augmented size by using scaling which is multiplying or dividing real dimensions by a constant factor. We use scaling when representing geographic locations on a map.

We are given the scale on a map as 1:20,000,000.

Two cities are 6 cm on the map. The actual distance is obtained by multiplying:

6 * 20,000,000 = 120,000,000 cm

Divide by 100 to convert to meters and by 1,000 to convert to km 120,000,000/100/1,000=1,200 Km

The actual distance between the cities is 1,200 Km

5 0

3 years ago

Sound travels through air at about 344 meters per seconds when the temp. is 20 degrees c. If Enrique lives 2 kilometres from the

Vaselesa [24]

Answer:

(344*20) + ( 2*20) = (20*2) = ?

Step-by-step explanation:

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3 years ago

Olivia has c comic books. Jackie has 3 times as many comic books as Olivia. Write an

Nana76 [90]

Answer:

Step-by-step explanation:

Hope this helps!

Have a nice day :)

5 0

3 years ago

Answer choices 216 cm 247 cm 297 cm 337 cm

Natalija [7]

297 cm is the total surface area of the square pyramid

7 0

3 years ago

What is the quadratic regression equation for the data set? PLEASEE HELP ME

Soloha48 [4]

You're trying to find constants $a_0,a_1,a_2$ such that $\hat y=a_0+a_1\hat x+a_2{\hat x}^2$ . Equivalently, you're looking for the least-square solution to the following matrix equation.

$\underbrace{\begin{bmatrix}1&6&6^2\\1&3&3^2\\\vdots&\vdots&\vdots\\1&9&9^2\end{bmatrix}}_{\mathbf A}\underbrace{\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}}_{\mathbf x}=\underbrace{\begin{bmatrix}100\\110\\\vdots\\70\end{bmatrix}}_{\mathbf b}$

To solve $\mathbf{Ax}=\mathbf b$ , multiply both sides by the transpose of $\mathbf A$ , which introduces an invertible square matrix on the LHS.

$\mathbf{Ax}=\mathbf b\implies\mathbf A^\top\mathbf{Ax}=\mathbf A^\top\mathbf b\implies\mathbf x=(\mathbf A^\top\mathbf A)^{-1}\mathbf A^\top\mathbf b$

Computing this, you'd find that

$\mathbf x=\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}\approx\begin{bmatrix}121.119\\-3.786\\-0.175\end{bmatrix}$

which means the first choice is correct.

8 0

4 years ago