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Gennadij [26K]
3 years ago
10

Avril is reading the first Harry Potter book, Harry Potter and the Sorcerer's Stone. The book has a total of

Mathematics
1 answer:
Svetach [21]3 years ago
4 0
Yes, she will finish it. She would have 22 min left.
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What is the x value such that y=15 - 3x and y = 0
qwelly [4]
-3x+15=0
Add -15 both sides
-3x=-15
Divided by -3 both sides
x=-15/-3
x=5
3 0
3 years ago
Read 2 more answers
>
oksian1 [2.3K]

Complete Question:

Let x and y be positive integers and x be greater than y.

11x/11y = ?

Answer:

11x/11y = x/y

Step-by-step explanation:

Given

x > y

Required

11x/11y

From the question, we understand that x is greater than y (i.e. x > y)

Also, we'll assume that y ≠ 0, in other not to result in an undefined result.

So,

11x/11y

Divide the numerator and denominator by 11

(11x ÷ 11)/(11y ÷ 11)

The result of the division is:

(x)/(y)

x/y

Hence,

11x/11y = x/y for x > y and y ≠ 0

3 0
3 years ago
Someone pls help I need this like now pls lots of points and brainliest
Serjik [45]

Answer:

  • See below

Step-by-step explanation:

<h3>#7</h3>
  • 5⁵(16²5³)³ = 5⁵(2⁴)³(5³)³ = 5⁵2¹²5⁹ = 5¹⁴2¹²
<h3>#8</h3>
  • (8⁴5³/8⁵)² = (5³/8)² = (5³)²/(2³)² = 5⁶ / 2⁶
<h3>#9</h3>
  • (5⁸3⁷/5⁴)¹⁰ = (5⁴3⁷)¹⁰ = (5⁴)¹⁰(3⁷)¹⁰ = 5⁴⁰3⁷⁰
<h3>#10</h3>

<u>Multiplying powers with same base:</u>

  • a^b*a^c=a^{b+c}
  • Same base with powers added up

<u>Multiplying powers with same exponent but different base:</u>

  • a^b*c^b=(ac)^b
  • Same exponent with bases multiplied
8 0
3 years ago
Find the value of Y for the given value of x
LUCKY_DIMON [66]
Y=-4x+6 x=1
y=-4(1)+6
y=-4+6
y=2


6 0
3 years ago
I need help on question 1 of symbolic representation
monitta

Answer:

f(x) = 0x + 5

Step-by-step explanation:

Lets use the slope formula to determine the slope of this graph:

m=\frac{y_{2}-y_{1}  }{x_{2}-x_{1} } \\\\m=\frac{5-5 }{4-(-7)} \\\\m=0

SO we know the slope is zero.

If we know the slope is zero, then the y intercept must be at 5.

So the equation would be:

f(x) = 0x + 5

6 0
3 years ago
Read 2 more answers
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