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AleksandrR [38]
3 years ago
15

Thread-like structures that are found in the nucleus of a cell that contains all DNA

Biology
1 answer:
Dovator [93]3 years ago
6 0

Answer:

Deoxyribonucleic Acid

Explanation:

it jus is

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Of the nine gigatons of carbon released into the atmosphere by human activity how much is taken up by ocean sediments? how much
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26% is taken up by ocean sediment. 26% taken by net terrestrial uptake and Human activities, especially conventional farming activities and burning fossil carbon as fuel, have disturbed the carbon cycle's balance, leading to more carbon dioxide being released into the atmosphere than is being taken up by plants
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Wether the apple has a taproot or a fibrous root
Zarrin [17]

Answer:

taproot

Explanation:

Apple trees roots consist of a deep taproot and lateral fibrous roots. The taproot is analogous to the carrot, which is a taproot. Lateral fibrous roots can extent to more than twice the spread of the canopy of the apple tree and are influenced by soil, water availability and competition from the roots of other plants.

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How would you state the events of prohase of mitosis?
dsp73

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3 years ago
BRAINLIESTTT ASAP!!
Romashka [77]

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3 years ago
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You sampled 1000 individuals from a population of mosquitoes to test whether they are in Hardy-Weinberg Equilibrium for a gene D
Marysya12 [62]

Answer:

The population is not following the Hardy-Weinberg equilibrium.

Explanation:

Hardy-Weinberg  proposed that the population will remain in the equilibrium if they are not affected with the external natural force like genetic drift, mutation and many others. The gene pool of a population will remain in equilibrium state for generations.

The mathematical expression for the Hardy-Weinberg are

Genotypic frequency is p²+q²+2pq=1

Allele frequency is p+q=1

where p-dominant allele,

q-recessive allele

Therefore,calculating expected frequency of allele q,

q² (recessive genotype)-  q²+2pq/1000

= 22+188/1000

=210/1000

= 0.21

q= 0.45

Calculating expected frequency of allele p,

Using p+q=1

p=1-q

p= 0.55 (expected)

Calculating observed value of frequency of p,

p²= p²+2pq/1000

= 790+188/1000

= 978/1000

= 0.978

p = 0.988 (observed)

Since the expected frequency does not match the observed frequency therefore the population is not under the Hardy-Weinberg equilibrium and the gene pool is disturbed.

4 0
3 years ago
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