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Novosadov [1.4K]
3 years ago
15

A father is 28 years older than his daughter. In six years' time, he will be three times her age. Find their present ages.

Mathematics
2 answers:
konstantin123 [22]3 years ago
8 0

Answer:

<h2>Daughter's age = 6</h2><h2>Father's age = 34</h2>

Step-by-step explanation:

Let the age of daughter be x

Then the age of father will be x + 28

<u>In 6 years time:-</u>

The age of father = x + 28 + 2 = 30 + x

The age of daughter = x + 6

According to the question,

Father will be three times the age of his daughter.

30 + x = 3(x + 6)

30 + x = 3x + 18

x - 3x = 18 - 30

-2x = - 12

x = - 12/-2

x = 6

So therfore,

Daughter's present age = 6 years

Father's present age = 34 years

Hope this helps :)

frozen [14]3 years ago
8 0

A father is 28 years older than his daughter. In six years' time, he will be three times her age. Find their present ages.


Please include your working out!!
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