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IrinaVladis [17]
3 years ago
9

of a football team's season touchdowns, about 43% came by passing. If the team scored 28 touchdowns, how many were by other mean

s?​
Mathematics
1 answer:
yulyashka [42]3 years ago
3 0

43% were from passing so 100% - 43% = 57% came by other means.

28 x 57% = 28 x 0.57 = 16

16 came from different means.

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2.5% of a population are infected with a certain disease. There is a test for the disease, however the test is not completely ac
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Answer:

P(disease/positivetest) = 0.36116

Step-by-step explanation:

This is a conditional probability exercise.

Let's name the events :

I : ''A person is infected''

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NT : ''The test is negative''

The conditional probability equation is :

Given two events A and B :

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(A ∩ B) is the event where A and B happened at the same time

In the exercise :

P(I)=0.025

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P(PT/I)=0.904\\P(PT/NI)=0.041

We are looking for P(I/PT) :

P(I/PT)=P(I∩ PT)/ P(PT)

P(PT/I)=0.904

P(PT/I)=P(PT∩ I)/P(I)

0.904=P(PT∩ I)/0.025

P(PT∩ I)=0.904 x 0.025

P(PT∩ I) = 0.0226

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P(PT/NI)=P(PT∩ NI)/P(NI)

0.041=P(PT∩ NI)/0.975

P(PT∩ NI) = 0.041 x 0.975

P(PT∩ NI) = 0.039975

P(PT) = P(PT∩ I)+P(PT∩ NI)

P(PT)= 0.0226 + 0.039975

P(PT) = 0.062575

P(I/PT) = P(PT∩I)/P(PT)

P(I/PT)=\frac{0.0226}{0.062575} \\P(I/PT)=0.36116

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3 years ago
Use the data in the table to complete the sentence.
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Answer:

x is plus 1 and y is minus 1.

Step-by-step explanation:

thats what i put and marked it as correct on edgenuity.

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